Hey!!
here is your answer >>>
1) 3x - 10 > 11
let's take this as 3x - 10 = 11
3x = 21
x = 7
So, The numbers of X are always more than 7
2) 9x + 2 < 5
9x + 2 = 5
9x = 3
x = 1÷2
The numbers of X are always less than 1 ÷ 2
3) 2x + 8 < 6
2x + 8 = 6
2x = 2
x = 1
The numbers of X are less than 1
4) 4x - 3 < 12
4x - 3 = 12
4x = 15
x = 15 ÷ 4
The numbers of X are less than 15 ÷ 4
5) 2 ( 9 + x ) > 20
2 ( 9 + x ) = 20
9 + x = 10
x = 1
The numbers of X are more than 1
We can solve the rest using this
Hope my answer helps!
X+4x+6x=
All of the variables are x so you don't have to do anything
6x+4x=10x
there is still one x left
x = 1
10x+x = 11x
0.20 so %20 because there is 20 100ths between that
The system of Roman numerals is based on using special symbols to denote decimal digits I=1, X=10, C=100, M=1000, and their halves V=5, L=50, D=500. Positive integers are written by repeating these numerals.
Brainliest?
Borrow money from a relative, use credit cards to build up good credit, do a fundraiser. This is what you could do to pay off debts
