Answer:
a) weight  of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy  =  0     and  ∑Fx  =  0
Forces acting on the car:
The external force   490 lbs
weight of the car   uknown
Normal force
sin∠10°  =  0,174
cos∠10° = 0.985
∑Fx  =  0         mg*sin10°- 490 = 0      ∑Fy =  0      mg*cos10° - N  =  0
mg*0,174= 490
mg  =  490 / 0,174
mg = 2816,1 lbs
weight  of the car = 2816,1 lbs
The Normal force
 mg*cos10° - N  =  0        2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
 
        
             
        
        
        
 x is the number of adults and y is the number of children.
   x + y = 12
<span>14x + 10y = 140
lets multiply the first equation by -10 and then add it to the second equation:
-10x - 10y = -120
</span>14x + 10y = <span>140
</span>-----------------------
4x + 0 = 20
x = 20/4
x = 5
then substitute in the original equation:
x + y = <span>12
</span>5 + y = <span>12
</span>y = 12 - 5
y = 7
therefore there were 5 adults and 7 children
        
             
        
        
        
Answer:
is this the right question please??
 
        
             
        
        
        
Answer:
Step-by-step explanation:
9n-2
 
        
             
        
        
        
Answer:
6
Step-by-step explanation:
(8:100) * 75
(8*75) : 100
600:100 = 6