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lana [24]
3 years ago
5

The mean shoe size of the students in a math class is 7.5. Most of the shoe sizes fall within 1 standard deviation, or between a

size 6 and a size 9.
What is the standard deviation of the shoe size data for the math class?


1.5

2.7

3.0

3.8
Mathematics
2 answers:
Zarrin [17]3 years ago
6 0

Answer:

1.5


Step-by-step explanation:

The mean is the Middle number.

1 standard deviation in both sides of 7.5 makes it between 6 and 9.

<u>What is the </u><u>"common difference"</u><u> in 6 to 7.5 and from 7.5 to 9?</u>

7.5-6=1.5

and

9-7.5=1.5


So, we would say the standard deviation is 1.5

Answer choice A is right.

sladkih [1.3K]3 years ago
3 0

Answer:

The Answer On Edge Is A.), Have Fun Dreamers!

Step-by-step explanation:

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taurus [48]

Answer:-18/15

Step-by-step explanation:

15g+18=0

15g=-18

divide both sides by 15

g=-18/15

8 0
3 years ago
Out of 120 students in exam, 2/3 of them passed. How many students passed?​
LenKa [72]

Out of 120 students in exam, 2/3 of them passed. How many students passed?

now,

no of students passed = 2/3×120

= 0.66×120

=80...

therefore <em>8</em><em>0</em><em> </em><em> </em><em>students</em><em> </em><em>were</em><em> </em><em>passed</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
3 years ago
Read 2 more answers
Can someone help please
myrzilka [38]
<h3>Answer:   15x^(7/3) - 8x^(7/4) + x + 9000</h3>

=========================================================

Explanation:

If you know the cost function C(x), to find the marginal cost, we apply the derivative.

Marginal cost = derivative of cost function

Marginal cost = C ' (x)

Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.

\text{Cost} = \text{antiderivative of marginal cost}\\\\\displaystyle C(x) = \int \left(35x^{4/3} - 14x^{3/4} + 1\right)dx\\\\

C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).

To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.

Therefore, we go from this

C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

to this

C(x) = 15x^{7/3} - 8x^{7/4} + x + 9000\\\\

which is the final answer.

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