Suppose a large population has a mean μand standard deviation σ, and a simple randomsample of size nis taken. The sampling distr
ibution of the sample mean xhas mean andvariance respectively equal to(a)μ/nand σ2/n.(b)μand σ/n.(c)μ/nand σ2/n2.(d)μand σ2/n.
1 answer:
Answer:
(d) μ and σ²/n
Step-by-step explanation:
In a sampling distribution of sample means, the mean is equal to the population mean, which is μ.
The standard deviation of the sampling distribution of sample means is given by
σ/√n.
The variance of a distribution is the square of the standard deviation; this means the variance of the sampling distribution of sample means would be
(σ/√n)² = σ²/(√n)² = σ²/n
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