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MAVERICK [17]
4 years ago
8

Suppose a large population has a mean μand standard deviation σ, and a simple randomsample of size nis taken. The sampling distr

ibution of the sample mean xhas mean andvariance respectively equal to(a)μ/nand σ2/n.(b)μand σ/n.(c)μ/nand σ2/n2.(d)μand σ2/n.
Mathematics
1 answer:
My name is Ann [436]4 years ago
4 0

Answer:

(d) μ and σ²/n

Step-by-step explanation:

In a sampling distribution of sample means, the mean is equal to the population mean, which is μ.

The standard deviation of the sampling distribution of sample means is given by

σ/√n.

The variance of a distribution is the square of the standard deviation; this means the variance of the sampling distribution of sample means would be

(σ/√n)² = σ²/(√n)² = σ²/n

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vlabodo [156]

The area of the sector is 5.9 m²

Step-by-step explanation:

The problem pertains to the area of an arc.

We know that area of the arc is given by= (central angle/360°)*π*r ²

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3 years ago
one night a theater sold 548 movie tickets. an adult’s costs $6.50 an child’s cost $3.50. in all, $2,881 was takin in. how many
gavmur [86]

Answer:

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Step-by-step explanation:

This sort of problem is easily solved by defining a variable to be the quantity of the higher-value contributor. Here, we can let x represent the number of adult tickets. Then total revenue is ...

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321 adult tickets and 227 child tickets were sold.

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boyakko [2]

Answer:

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We know that in a parallelogram opposite sides are congruent.

So, in the given parallelogram side LM ≅ side NO

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So, value of x = 19

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3 years ago
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