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tresset_1 [31]
3 years ago
12

A car is speeding at 9595 miles per hour. How many meters per minute is the vehicle travelling?

Mathematics
1 answer:
sergejj [24]3 years ago
4 0
This is the concept of rates, we are required to convert on rate to another. The We have been given a car that is speeding at 9595 mph, we are required to convert this to meters per minute;
Here we proceed as follows;
1 mile= 1609.34 miles/hour
1 hour= 60 min 
thus to convert from miles per hour to meters per minute we shall have:
speed=distance/time
our distance will be:
distance=9595*1609.34=15,441,617.3 meters
time=(60*1)=60 minutes
thus;
speed=15,441,617.3/60
speed=257,360.2882 meters per minuts
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3 years ago
Use substitution to solve the following system of equations. What is the value of y? {3x+2y=12{5x−y=7 A) y = -3B) y = 3C) y = -2
Vlad [161]

<em>Answer</em>

B) y = 3

<em>Step-by-step explanation</em>

Given the system of equations:

\begin{gathered} 3x+2y=12\text{ \lparen eq. 1\rparen} \\ 5x-y=7\text{ \lparen eq. 2\rparen} \end{gathered}

Isolating x from equation 1:

\begin{gathered} 3x+2y-2y=12-2y \\ 3x=12-2y \\ \frac{3x}{3}=\frac{12-2y}{3} \\ x=\frac{12}{3}-\frac{2}{3}y \\ x=4-\frac{2}{3}y\text{ \lparen eq. 3\rparen} \end{gathered}

Substituting equation 3 into equation 2 and solving for y:

\begin{gathered} 5(4-\frac{2}{3}y)-y=7 \\ 5\cdot4-5\cdot\frac{2}{3}y-y=7 \\ 20-\frac{10}{3}y-y=7 \\ 20-\frac{13}{3}y=7 \\ 20-\frac{13}{3}y-20=7-20 \\ -\frac{13}{3}y=-13 \\ (-\frac{3}{13})\cdot-\frac{13}{3}y=(-\frac{3}{13})\cdot-13 \\ y=3 \end{gathered}

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1 year ago
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<span>Hope it helps! :D</span>

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3 years ago
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leva [86]

Answer:

D: 5 : 8 and 20 : 32

Step-by-step explanation:

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Answer:

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