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Makovka662 [10]

4 years ago

6

Which statement is true about the equation 4.5z = 4.5z – 4.25 + 6.25? (1 point) It has no solution. It has one solution. It has

two solutions. It has infinitely many solutions.

1 answer:

MakcuM [25]4 years ago

5 0

I think it would be it has no solutions, because if you solve for z, the z's cancel each out and you would get 0=2 with is not true, so there would not be any solutions.

4.5z=4.5z-4.25+6.25
4.5z-4.5z=-4.25+6.25
0=2
no solution

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Math help- 14 points!

Anit [1.1K]

Answer:

yeah he is right the answer is the photo

Step-by-step explanation:

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3 years ago

Mark gathered data about the number of pink and red flowers that bloomed on several of his flowering shrubs. The scatter plot sh

fgiga [73]

The scatter plot showing data gathered and line of best fit is attached below :

Answer:

69

Step-by-step explanation:

Given the regression model :

y = 1.73x + 0.0924

Where,

y = number of pink flowers

x = Red flowers

Slope = 1.73

Intercept = 0.0924

The number of pink flower that are predicted to bloom on a shrub of 40 red flowers :

Put x = 40 and calculate the value of y

y = 1.73(40) + 0.0924

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Number of pink flowers = 69

8 0

3 years ago

A. What is the vertex of the equation y = (x - 4)??

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Good morning,

Answer:

(4 , 0)

Step-by-step explanation:

THe vertex of y = (x - 4)² is (4,0).

Look at the photo below for the graph.

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8 0

4 years ago

Both the La Plata river dolphin (Pontoporia blainvillei) and

Citrus2011 [14]

Answer:

<em>1. A sperm whale is </em><em>3</em><em> </em><em>orders of magnitude</em><em> heavier than a La Plata river dolphin; 2. The radius of the larger ball is </em><em>one (1) order of magnitude</em><em> bigger than the radius of the smaller ball; 3. The volume of the larger ball is </em><em>3 orders of magnitude</em><em> bigger than the volume of the smaller ball</em>.

Step-by-step explanation:

If we expressed a number as:

$\\ N = a * 10^{b}$ (1)

Where

$\\ \frac{1}{\sqrt{10}} \leq a < \sqrt{10}$ (2)

or

$\\ 1 \leq a < 10$ (3)

Then, <em>b</em> represents the <em>order of magnitude </em>of such a number (<em>Order of magnitude (2020), </em>in Wikipedia).

The order of magnitude can be defined as "...the smallest power of ten needed to represent a quantity" (Weisstein, Eric W. "Order of Magnitude". From MathWorld--A Wolfram Web Resource).

Having gathered all this information, we can proceed as follows:

<h3>First case</h3>

The<em> La Plata river dolphin</em> weighs between 30 and 50kg and the sperm whale weighs between 35,000 and 40,000kg.

Then, considering (1) and (3) to express the dolphin and whale's weight (since in this way the order of magnitude is the same as the exponent part in the <em>scientific notation</em>):

$\\ 30kg \leq Dolphin_{weight} \leq 50kg$

$\\ 3*10^{1}kg \leq Dolphin_{weight} \leq 5*10^{1}kg$

$\\ 35000kg \leq Whale_{weight} \leq 40000kg$

$\\ 3.5*10^{4}kg \leq Whale_{weight} \leq 4.0*10^{4}kg$

Since the range for the weights are in the same order of magnitude for both dolphin and whale (considering the definition above):

$\\ Dolphin_{weight} = 10^{1}\;(order\;of\;magnitude=1)$

$\\ Whale_{weight} = 10^{4}\;(order\;of\;magnitude=4)$

Then

$\\ \frac{Whale_{weight} = 10^{4}}{Dolphin_{weight} = 10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = \frac{10^{4}}{10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{4-1}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{3}$

Thus

<em>A sperm whale is </em><em>3</em><em> </em><em>orders of magnitude</em><em> heavier than a La Plata river dolphin.</em>

<h3>Second case</h3>

Following the same reasoning, we can conclude that <em>the radius of the larger ball is </em><em>one (1) order of magnitude</em><em> bigger than the radius of the smaller ball:</em>

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = \frac{10^{1}}{10^{0}}$

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = 10^{1-0} = 10^{1}$

<h3>Third case</h3>

For this case, we need to calculate <em>the volume of a sphere</em> for both radii (1cm and 10cm).

The volume of a sphere is

$\\ V_{sphere} = \frac{4}{3}*\pi*R^{3}$

Then, the volume of the <em>ball of radius 1cm</em> is:

$\\ V_{radius=1} = \frac{4}{3}*\pi*(1cm)^{3}$

$\\ V_{radius=1} \approx 4.19*10^{0}cm^{3}$

And, the volume of the <em>ball of radius 10cm</em> is:

$\\ V_{radius=10} = \frac{4}{3}*\pi*(10cm)^{3}$

$\\ V_{radius=10} \approx 4.19*10^{3}cm^{3}$

Thus

$\\ \frac{10^{3}}{10^{0}} = 10^{3}$

As a result, <em>the volume of the larger ball is </em><em>3 orders of magnitude</em><em> bigger than the volume of the smaller ball</em>.

4 0

3 years ago

How many solutions does y=2x+1 and x=-3 have

Nikolay [14]

Answer:

- 5

Step-by-step explanation:

given,

the relation is y=2x+1

if x=-3 than, y =2x+1

=2 * (-3)+1

= -6+1

-5

hence, the required answer is - 5

I found any one solution of given question.

7 0

3 years ago