P a p a party party p q p w party
Answer:
Step-by-step explanation:
Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.
i.e. Sample mean = 1040 and
Sample std dev s = 25 gm
Sample size n = 100
Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm

Normal curve would be with mean 1040 and std deviatin 25
b) P(X>1115)
= 1-0.9987
=0.0013
i.e. 0.13% would receive a bag that had a weight greater than 1115 grams
Since it starts at 12 and is increasing by 5 each time, the 70th term will be;
12 + 5(70)
12 + 350
362
362 is the 70th term of the sequence.
1/6* (15a+20b)
= 1/6* 15a + 1/6* 20b (Distributive property)
= 2.5a + 10/3*b
The final answer is 2.5a+ 10/3b
Hope this helps~