Answer:
Step-by-step explanation:
Not sure what form you need this in, but it really doesn't matter, as you'll see in the final equation. I used the vertex form and solved for a:
We are given the vertex (h, k) as the origin (0, 0), and we have a point that the graph goes through as (4, -64). That's our x and y. Plugging in what we have:
gives us
-64 = 16a and
a = -4. That means that the quadratic equation is
which is both vertex form and standard form here, no difference.
Answer: for a sum of 7 would either be 6 and 1, 5 and 2 or 4 and 3. you can roll a double 1,2,3,4,5,6. the sum of 8 would be 2 and 6, 3 and 5 and a double 4,
Step-by-step explanation:
well the there are six sides on a die so 6 x 2 is 12 so the max sum you can get is 12. So you take 7 and you start adding up to 7, same thing for sum of 8. since there is 6 sides and a pair of dices you will roll six doubles
(1,2)
The solution is where the lines intersect so you can see they intersect at (1,2)
Answer:
c
Step-by-step explanation:
Since both equations express y in terms of x we can equate the right sides
3x + 5 = - x + 3 ( add x to both sides )
4x + 5 = 3 ( subtract 5 from both sides )
4x = - 2 ( divide both sides by 4 )
x = - 0.5
substitute x = - 0.5 in either of the 2 equations
using y = - x + 3 then y = 0.5 + 3 = 3.5
solution is (- 0.5, 3.5 ) → c
3x+15= 5x
8y-72= 9y
9a+18= 2a
3b-27= 9b
5c+40= 8c
6c+18= 3c
8c-8= c/1c
5x-10= 2x
2b-16= 8b
7c-35= 5c
