Answer:
Final temperature = 22.21 °C
Explanation:
Heat gain by ethanol = Heat lost by water
Thus,
Where, negative sign signifies heat loss
Or,
<u>For ethanol:
</u>
Density = 0.789 g/mL
Volume = 55.0 mL
Considering the expression for density as:
So,
So, Mass= Density*Volume = 0.789 g/mL * 55.0 mL = 43.395 g
Initial temperature = 9.0 °C
Specific heat of ethanol = 2.57 J/g°C
<u>For water:
</u>
Density = 1.0 g/mL
Volume = 55.0 mL
Considering the expression for density as:
So,
So, Mass= Density*Volume = 1.0 g/mL * 55.0 mL = 55.0 g
Initial temperature = 28.6 °C
Specific heat of water = 0.450 J/g°C
So,
<u>Final temperature = 22.21 °C </u>
Answer:
Explanation:
Hello,
In this case, temperature-variable version of the Arrhenius equation is applied in order to compute the activation energy as shown below:
Thus, we replace each variable considering k2=3*k1 (tripling):
Best regards.