Question

What is the boiling point of a solution that contains 3 moles of KBr in 2000 g of water?

Answer 1

Answer:

C. 101.5°C

Explanation:

The computation of the boiling point of a solution is shown below:

As we know that

$\Delta T = i K_bm$

where,

i = Factor of Van’t Hoff i.e 2KBr

K_b = Boiling point i.e 0.512° C

m = molality  $= \frac{Moles\ of\ solute}{Solvent\ mass}$

Now place the values to the above formula

So, the boiling point is

$(T - 100^\circ C) = 2\times 0.512^\circ \times \frac{3.00\ ml}{2.00\ kg}$

After solving this, the t is

= 100° C + 1.536° C

= 101.536° C

Hence, the correct option is C.