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qwelly [4]
3 years ago
15

Q26.When added to 20 cm of 0.5 M sulphuric acid, which substance would give a neutral solution?​

Chemistry
1 answer:
wariber [46]3 years ago
4 0

Answer:

Adding sodium or potassium hydroxide in amounts sufficient to convert all the H2SO4 into Na2SO4 would approximately neutralize the solution. The error would be the result of the imbalance between the basicity of the hydroxide and the acidity of the bisulfate (HSO4) anion. An adjustment in concentration would have to be made to achieve an accurate approximate pH of 7. But then you didn’t ask how much we would need to add.

Explanation:

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3 years ago
Read 2 more answers
Please help! Thanks!
olya-2409 [2.1K]

Answer:

<u>The deviations are :</u>

  • <u>The activation energy which changes with temperature</u>
  • <u>The arrhenius constant which depends on the temperature</u>

Explanation:

  • There are deviations from the Arrhenius law during the glass transition in all classes of glass-forming matter.
  • The Arrhenius law predicts that the motion of the structural units (atoms, molecules, ions, etc.) should slow down at a slower rate through the glass transition than is experimentally observed.
  • In other words, the structural units slow down at a faster rate than is predicted by the Arrhenius law.
  • <em>This observation is made reasonable assuming that the units must overcome an energy barrier by means of a thermal activation energy. </em>
  • The thermal energy must be high enough to allow for translational motion of the units <em>which leads to viscous flow of the material.</em>

  • Both the Arrhenius activation energy and the rate constant k are experimentally determined, and represent macroscopic reaction-specific parameters <em>that are not simply related to threshold energies and the success of individual collisions at the molecular level. </em>
  • Consider a particular collision (an elementary reaction) between molecules A and B. The collision angle, the relative translational energy, the internal (particularly vibrational) energy will all determine the chance that the collision will produce a product molecule AB.
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6 0
3 years ago
What are deltaTb and deltaTf for an aqueous solution that is 1.5g nacl in 0.250kg h2o? Given Kb=0.51 C/m and kr=1.86 C/m
bulgar [2K]

Answer:

T_f for given question is 2.79 and T_b is 0.52

\Delta T_b = I \times K_b \times m {i- vant hoff’s constant ; Kb- constant ; m molarity }

M = no. of moles of the solute present in one kg of solution

Let the weight of amount of solute be “w” and its molecular mass be “M”

Let the mass of the solvent in the given question be “x”

\Delta T_b = I \times K_b \times (w/M)/ x

\Delta T_b = I \times K_b \times w/Mx

\Delta T_b = 1 \times 0.51 \times1.5/(0.250 \times 58.44) = 0.052

\Delta T_f = M \times K_f = 1.86 \times 1.5 = 2.79

4 0
3 years ago
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