The changes that are common between sauce burning on a stove, and jewelry tarnishing, which is a chemical change.
How to define chemical and physical changes?
Chemical Change-
Any alteration that produces new chemical substances with distinct properties is considered a chemical change. Chemical reactions involve the rearrangement and recombination of elements and compounds to create new substances. Examples of chemical changes are listed below:
- Burning
- Digestion
- chemicals changing colors
- Tarnishing
- compost rotting
Physical Change-
A substance is not destroyed or transformed into something new by physical changes. A substance can undergo physical changes that alter its shape, size, or phase. The constituents of an element or compound do not change during a physical change. Examples of physical changes are listed below:
- Boiling water
- Chopping, Cutting, Carving
- Evaporation
- Freezing, Melting, Condensation
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Answer:
A. tungsten
Explanation:
Tungsten is a material which high melting point ie. does not melt easily incase of high temperature
Answer:
Methane
Explanation:
The gas that you could keep in an outdoor storage tank in winter in Alaska is Methane.
The reason is the extreme low temperature during the winter. The boiling point of butane is 44 ºF ( -1ºC) and that of propane is a higher -43.6 º F but still within the range of average minimum winter temperature in Alaska (-50 ªF). Therefore we will have condensation in the tanks and not enough gas pressure.
Methane having a boling point of -259 ºF will not condense at the low wintertime temperatures in Alaska.
Answer:
Option A. It has stayed the same.
Explanation:
To answer the question given above, we assumed:
Initial volume (V₁) = V
Initial temperature (T₁) = T
Initial pressure (P₁) = P
From the question given above, the following data were:
Final volume (V₂) = 2V
Final temperature (T₂) = 2T
Final pressure (P₂) =?
The final pressure of the gas can be obtained as follow:
P₁V₁/T₁ = P₂V₂/T₂
PV/T = P₂ × 2V / 2T
Cross multiply
P₂ × 2V × T = PV × 2T
Divide both side by 2V × T
P₂ = PV × 2T / 2V × T
P₂ = P
Thus, the final pressure is the same as the initial pressure.
Option A gives the correct answer to the question.