Answer:
maximum value of y = 3
Step-by-step explanation:
line Starts at -4 , 0 & turns at - 1 , 3
Slope = (3 - 0)/(-1 -(-4)) = 3/3 = 1
y = x + c
=> 0 = - 4 + c => c = 4
=> y = x + 4
line after turning crosses the y-axis at (0, 2) and the x-axis at (2, 0)
slope of this line : (0-2)/(2-0) = -1
y = - x + c
2 = 0 + c => c = 2
=> y = - x + 2
=> y = 2 - x
Values Drawn
x y
-4 0
-3 1
-2 2
-1 3
0 2
1 1
2 0
We are asked to determine the value of a such that the function f(x) = ax^2 + 5 is fit for the point given (-1,2). In this case, we substitute 2 to y and -1 to x. The result is then 2 = a*(-1)^2 + 5 ; 2 = a + 5; a is then equal to -3
What you do is you distribute the 5.
So your answer would be 5x+15
Answer:
15%
Step-by-step explanation:
90-75=15
