All categories

3 years ago

Find the area. 7 m 4 m 4 m square meters

Mathematics

2 answers:

FrozenT [24]3 years ago

7 0

The answer to the question you asked will be 112

yan [13]3 years ago

3 0

Answer: 112

Step-by-step explanation: can i get brainliest

You might be interested in

Use the table to write a quadratic function in vertex form. Then rewrite the function in standard form.

Kisachek [45]

Answer:

Step-by-step explanation:

The graph decreases at first, then changes direction at (2, 5).

y = a(x-2)^2 + 5

Plug in (1,11) and solve for a:

11 = a(1-2)^2 + 5

a = 6

Equation in vertex form:

y = 6(x-2)^2 + 5

8 0

3 years ago

I NEED HELP PLEASE!!!! Given a real world problem, can you find the unit rate?

Yuliya22 [10]

Here is an example:

Josh bought 7 apples for $21.

21/7 is 3, so one apple costs $3. This is the unit rate.

21/7 simplifies to 3/1, that’s another way to think about it. Simplify the fraction until the denominator is 1.

Hope this helps! Tell me if you have any questions!

3 0

3 years ago

Boris choos three diffrent numbers.the sum of the three numbers is 36.One of trh numbers is a cube number.the other two number a

inna [77]

Answer:

4,5,27

Problem:

Boris chose three different numbers.

The sum of the three numbers is 36.

One of the numbers is a perfect cube.

The other two numbers are factors of 20.

Step-by-step explanation:

Let's pretend those numbers are:

$a,b, \text{ and } c$ .

We are given the sum is 36: $a+b+c=36$ .

One of our numbers is a perfect cube. $a=n^3$ where $n$ is an integer.

The other two numbers are factors of 20. $bk=20$ and $ci=20$ where $a,c,i, \text{ and } k \text{ are integers}$ .

$n^3+\frac{20}{k}+\frac{20}{i}=36$

From here I would just try to find numbers that satisfy the conditions using trial and error.

$3^3+\frac{20}{2}+\frac{20}{2}$

$27+10+10$

$47$

$3^3+\frac{20}{4}+\frac{20}{5}$

$27+5+4$

$36$

So I have found a triple that works:

$27,5,4$

The numbers in ascending order is:

$4,5,27$

4 0

3 years ago

of 101 randomly selected adults, 35 were found to have high blood pressure. construct a 95% confidence interval for the true per

satela [25.4K]

Answer:

33%

Step-by-step explanation:

6 0

3 years ago

The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla

forsale [732]

Answer:

Speed at Equator = 463.97 meters per second

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

Step-by-step explanation:

The formula is:

$v=\frac{2 \pi R}{T}$

Where

v is speed

R is radius

T is time

and another formula for centripetal acceleration:

$a_c=\frac{4 \pi^{2} R}{T^2}$

Now,

at equator, the radius is radius of earth (given), time in seconds is

T = 24 * 60 * 60 = 86,400

THus,

$v_E=\frac{2 \pi (6.38*10^{6}}{86,400}=463.97$

Speed at Equator = 463.97 meters per second

Centripetal Acceleration:

$a_{cE}=\frac{v_E^2}{R_E}=\frac{463.97}{6.38*10^{6}}=3.37*10^{-2}$

Centripetal Acceleration at Equator = $3.37*10^{-2}$ meters per second squared

At 30.0° north of the equator:

$R_N=R_E Cos (30)= (6.38*10^6)Cos(30)=5.53*10^6$

Now,

Speed = $v_{30N}=\frac{2 \pi (5.53*10^6)}{86,400}=401.79$

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration:

$a_{30N}=\frac{v_E^2}{R_E}=\frac{401.79}{5.53*10^6}=2.92*10^{-2}$

Centripetal Acceleration at 30 degrees north of equator = $2.92*10^{-2}$ meters per second squared

4 0

3 years ago