9+2w
hopefully this helps!!
Answer: Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .
Step-by-step explanation:
Since the triangles are similar, the ratio of their sides are equal.
And we can count the number of blocks over which AC and A'C' is drawn and take them to be their length,
Therefore,
AC = 16
A'C'= 8
Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .
Measuring the tans of the angles by taking the ratio of opposite by adjacent, we get,
tanA = 
tanA'=
which means tanA= tanA'
The angles do not change.
Thus when transforming from ABC to A'B'C', the lengths are scaled by a factor of 0.5 .
Answer:
Step-by-step explanation:
From the information given,
Mark: 6,7,8,9,10
frequency:5,4,7,10,4
a) Range = highest mark - lowest mark
Range = 10 - 6 = 4
b) The number of students in the group is the sum of the frequency. Therefore,
Number of students = 5 + 4 + 7 + 10 + 4 = 30 students
c) Mean mark = (mark × frequency)/total frequency
[(6 × 5) + (7 × 4) + (8 × 7) + (9 × 10) + 10 × 4)]/ 30
Mean mark = (30 + 28 + 56 + 90 + 40)/30 = 244/30
Mean mark = 8.1
<span><span><span>s+12</span>+<span>3s</span></span>−8</span><span>=
<span><span><span><span>s+12</span>+<span>3s</span></span>+</span>−8
</span></span>Combine Like Terms<span>
<span><span><span>s+12</span>+<span>3s</span></span>+<span>−8</span></span></span><span>=
<span><span>(<span>s+<span>3s</span></span>)</span>+<span>(<span>12+<span>−8</span></span>)</span></span></span><span>=
<span><span>4s</span>+<span>4</span></span></span>
All you need to do is convert this to Kelvin.
Add 273.15 to Celcius to find Kelvin.
255.15 kelvin
