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Yakvenalex [24]
2 years ago
8

I need help with 5 plz also explain how to get it.

Mathematics
1 answer:
blagie [28]2 years ago
5 0
Sorry but i did not learn thiz
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Macy deposited $25,000 in a money market account earning 2.5% interest, compounded semiannually. What is Macy's return on this i
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After 4 years the rate would have happened 4 times making the initial deposit increase 10%. 10% of 25000 is 2500. So 25000 plus 2500 is $27500.
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Please draw and label two perpendicular line segments KL and MN
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So draw a cross! One line segment is KL and the other Mn
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In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

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notsponge [240]

Answer:

1.7 or 1 7/10

Step-by-step explanation:

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Answer:

its 10 am I think

Step-by-step explanation:

it says 2 hours until midnight. 12 - 2 = 10

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