1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ZanzabumX [31]
2 years ago
11

410x44 with parshal product

Mathematics
1 answer:
Olegator [25]2 years ago
4 0

Answer:

18040

Step-by-step explanation:

using partial product method, you get 18040

You might be interested in
Antonio moved boxes that weighed 26.5 pounds 34.2 pounds and 45.8 pounds. which is closest to number antonio moved all togehter
Andre45 [30]
B. 107 bc 26.5+34.2= 60.7+45.8= 106.5 round that to be 107.
7 0
2 years ago
Can anyone help me with this?
arsen [322]

Answer :The answer is B.

4 0
2 years ago
Read 2 more answers
For the function defined by f(t)=2-t, 0≤t<1, sketch 3 periods and find:
Oksi-84 [34.3K]
The half-range sine series is the expansion for f(t) with the assumption that f(t) is considered to be an odd function over its full range, -1. So for (a), you're essentially finding the full range expansion of the function

f(t)=\begin{cases}2-t&\text{for }0\le t

with period 2 so that f(t)=f(t+2n) for |t| and integers n.

Now, since f(t) is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L

where

b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt

In this case, L=1, so

b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt
b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}
b_n=\dfrac{4-2(-1)^n}{n\pi}

The half-range sine series expansion for f(t) is then

f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t

which can be further simplified by considering the even/odd cases of n, but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming f(t) is even/symmetric across its full range. In other words, you are finding the full range series expansion for

f(t)=\begin{cases}2-t&\text{for }0\le t

Now the sine series expansion vanishes, leaving you with

f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L

where

a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt

for n\ge0. Again, L=1. You should find that

a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3

a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt
a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}
a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}

Here, splitting into even/odd cases actually reduces this further. Notice that when n is even, the expression above simplifies to

a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0

while for odd n, you have

a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}

So the half-range cosine series expansion would be

f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t

Attached are plots of the first few terms of each series overlaid onto plots of f(t). In the half-range sine series (right), I use n=10 terms, and in the half-range cosine series (left), I use k=2 or n=2(2)-1=3 terms. (It's a bit more difficult to distinguish f(t) from the latter because the cosine series converges so much faster.)

5 0
3 years ago
Which mixed number is equivalent to this decimal?  8.00027  
bearhunter [10]
Is that even a number

4 0
3 years ago
Read 2 more answers
What do you think it would mean for two expressions to be equivalent? Explain.
ra1l [238]

Answer:

the answers would be the same

8 0
3 years ago
Other questions:
  • Pleaseee help me solve this
    6·2 answers
  • Mary is inscribing a square in the circle shown, but she is having difficulty remembering the process. Which summary describes t
    11·1 answer
  • How long is 3/4 of an hour
    12·2 answers
  • Harry buys 9 dozen eggs how many eggs does he have in all
    15·1 answer
  • 54+54788347589535222
    14·2 answers
  • Please solve the question below 1
    12·1 answer
  • Wayne earns 7%
    15·1 answer
  • Tony picked 5 1/2 bushels of tomatoes. He gave 1 3/8 bushels to his grandmother and sold the rest. Tony sold Answer bushels of t
    10·1 answer
  • Pls help I’m losing my mind
    5·2 answers
  • Find the solution of the given simultaneous equations<br> y = 2x - 3<br> 3x - 2y = 4
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!