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2 years ago

12

A recipe calls for 2/3 cup of butter. Sticks of butter are divided into 1/4 cup sections. How many sections of butter will the r

ecipe need?

2 answers:

Phoenix [80]2 years ago

5 0

Step-by-step explanation:

They answer is your mom

SOVA2 [1]2 years ago

4 0

Answer:

2 1/2?

Step-by-step explanation:

no

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What is the slope of (-3,-6) and (4,7)

Gelneren [198K]

Answer:

13/7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-(-6))/(4-(-3))

m=(7+6)/(4+3)

m=13/7

3 0

3 years ago

A man bought 42 stamps, some 13¢ and some 18¢. How many of each kind did he buy if the cost was $6.66?

OverLord2011 [107]

Let's call the 13¢ stamps a and the 18¢ stamps b: a+b = 42 and therefore a= 42-b (formula 1) 0.13a+0.18b= 6.66 In this formula, substitute the value of a according to formula 1: 0.13(42-b)+0.18b= 6.66 Multiply on the left to get rid of the parenthesis: 5.46-0.13b+0.18b= 6.66 Subtract 5.46 from both sides: -0.13b+0.18b= 1.20 Add on the left: 0.05b= 1.20 Divide both sides by 0.05 b= 24 You have 24 18¢ stamps and: 42-24= 18 13¢ stamps Check: (24 x 0.18) + (18 x 0.13)= 6.66 Correct.

5 0

3 years ago

mash [69]

Answer:I dont know but i think it is 1/2

Step-by-step explanation:

hope this helps

6 0

2 years ago

Given that 'n' is any natural numbers greater than or equal 2. Prove the following Inequality with Mathematical Induction

Oliga [24]

The base case is the claim that

$\dfrac11 + \dfrac12 > \dfrac{2\cdot2}{2+1}$

which reduces to

$\dfrac32 > \dfrac43 \implies \dfrac46 > \dfrac86$

which is true.

Assume that the inequality holds for <em>n</em> = <em>k </em>; that

$\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k > \dfrac{2k}{k+1}$

We want to show if this is true, then the equality also holds for <em>n</em> = <em>k</em> + 1 ; that

$\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2(k+1)}{k+2}$

By the induction hypothesis,

$\dfrac11 + \dfrac12 + \dfrac13 + \cdots + \dfrac1k + \dfrac1{k+1} > \dfrac{2k}{k+1} + \dfrac1{k+1} = \dfrac{2k+1}{k+1}$

Now compare this to the upper bound we seek:

$\dfrac{2k+1}{k+1} > \dfrac{2k+2}{k+2}$

because

$(2k+1)(k+2) > (2k+2)(k+1)$

in turn because

$2k^2 + 5k + 2 > 2k^2 + 4k + 2 \iff k > 0$

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2 years ago

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F(x) = x^2 - 5<br><br> g(x) = 4x - 4<br><br> Find (f-g) (5)

Verizon [17]

Hope this will help you

Have a nice day Ahead

4 0

3 years ago

Read 2 more answers