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EleoNora [17]
2 years ago
6

How does supply and demand affect consumers?

Mathematics
1 answer:
kondaur [170]2 years ago
4 0
I think it would be A. It controls how much we pay for goods and services, because if there is a high demand, and a limited supply, the cost will be high, if there is a large supply but low demand, then the cost will be lower.
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The equation d=m/v can be used to calculate the den
FromTheMoon [43]

yes you are right, density formula is :

density = mass ÷ vol

4 0
3 years ago
13.El alquiler de un coche cuesta 20 € al día, más 0'50 € por kilómetro recorrido. Halla la ecuación que calcula lo que se cobra
Alchen [17]

Answer:

La función es: f(x) = 20+0.5x

Step-by-step explanation:

La función que representa la condición sería:

f(x) = 20+0.5x

Donde:

  • 20 € es el costo por día
  • x es la cantidad de kilómetros
  • f(x) cobro por dia en función de los kilómetros

Espero te haya servido!

7 0
3 years ago
A closed container has 5.04 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10–24 grams.
never [62]

Answer:

Step-by-step explanation:

Each atom of the gas weighs 1.67 ⋅ 10−24 grams. 6.71 grams, because (5.04 + 1.67) ⋅ (1023⋅ 10−24 ) = 6.71. ... 0.67 grams, because (5.04 + 1.67) ⋅ (1023⋅ 10−24 ) = 6.71 ⋅ 10−1.

3 0
3 years ago
Antoine and Adriane are each at the top of a Ferris wheelAfter one revolution each will again be at the topWhich sinusoid (sine
Valentin [98]

Answer(s):

\displaystyle y = 100sin\:(\frac{\pi}{50}x + \frac{\pi}{2}) + 100 \\ y = 100cos\:\frac{\pi}{50}x + 100

Step-by-step explanation:

\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 100 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-25} \hookrightarrow \frac{-\frac{\pi}{2}}{\frac{\pi}{50}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{100} \hookrightarrow \frac{2}{\frac{\pi}{50}}\pi \\ Amplitude \hookrightarrow 100

<em>OR</em>

\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 100 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{100} \hookrightarrow \frac{2}{\frac{\pi}{50}}\pi \\ Amplitude \hookrightarrow 100

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of <em>sine</em>, then by all means, go for it, but be careful and follow what is explained here. Now, as you can see, the photograph on the right displays the trigonometric graph of \displaystyle y = 100sin\:\frac{\pi}{50}x + 100, in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the <em>co</em><em>sine</em> graph [photograph on the left], accourding to the <u>horisontal shift formula above</u>. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY <em>REALLY</em> ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the <em>sine</em> graph [photograph on the right] is shifted \displaystyle 25\:unitsto the right, which means that in order to match the <em>cosine</em> graph [photograph on the left], we need to shift the graph BACKWARD \displaystyle 25\:units,which means the C-term will be negative, and by perfourming your calculations, you will arrive at \displaystyle \boxed{-25} = \frac{-\frac{\pi}{2}}{\frac{\pi}{50}}.So, the sine graph of the cosine graph, accourding to the horisontal shift, is \displaystyle y = 100sin\:(\frac{\pi}{50}x + \frac{\pi}{2}) + 100.Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits \displaystyle [220, 100],from there to \displaystyle [120, 100],they are obviously \displaystyle 100\:unitsapart, telling you that the period of the graph is \displaystyle 100.Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the <em>midline</em>. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at \displaystyle y = 100,in which each crest is extended <em>one hundred units</em> beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

**I knew exactly what you were talking about the moment you posted this, so here was what you were looking for. It really does not matter which sinusoid and person you select because you will get the same information either way.

I am delighted to assist you at any time.

6 0
2 years ago
A pharmacist wishes to mix a solution that is 6% Minoxidil. She has on hand 100 ml of a 2% solution and wishes to add some 8% so
son4ous [18]

Answer:

200 ml

Step-by-step explanation:

It's proportions basically.

frst off, 2% of 100 ml is 2 ml, so the 100 ml solution has 2 ml of Minoxidil.

Eventually we want 6/100 to be the porportion.  so the total is going to be 100 (from the initial 100 ml) plus however much is needed x.  And we want the amount of Minoxidil to be 2 + 8 percent of x.  so this gets us the equation

6/100 = (2 + .08x)/(100+x)  Then we solve

(100 + x) 6/100 = 2 + .08x

(100 + x) 6 = 200 + 8x

600 + 6x = 200 + 8x

400 = 2x

x = 200

so they should add 200 ml

You can check too.  there is 100 + 200 ml of solution total and 2 + 16 ml of Minoxidil so that's 18/300 = 6/100

6 0
3 years ago
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