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enyata [817]
3 years ago
11

How many moles is 573.28 g of AgCl?

Chemistry
2 answers:
g100num [7]3 years ago
7 0

Answer:

4 moles

Explanation:

First, let's find the molar mass of AgCl. The molar mass of Ag is 107.87 and the molar mass of chlorine is 35.45 so the total mass is 107.87 + 35.45 = 143.32 grams per mole. Now all we need to calculate is 573.28 / 143.32 = 4 moles.

ohaa [14]3 years ago
3 0

Answer:

4 mols

Explanation:

Step 1: Find molar mass of AgCl

Ag - 107.8682

Cl - 35.45

Ag + Cl = 143.318 g/mol

Step 2: Conversion

573.26g AgCl (\frac{1 mol}{143.318 g})

We should get 4.00005, rounded to 4 mols as our answer.

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How many moles of MgS2O3 are in 205 g of the compound?
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