Question

How many moles is 573.28 g of AgCl?

Answer 1

Answer:

4 moles

Explanation:

First, let's find the molar mass of AgCl. The molar mass of Ag is 107.87 and the molar mass of chlorine is 35.45 so the total mass is 107.87 + 35.45 = 143.32 grams per mole. Now all we need to calculate is 573.28 / 143.32 = 4 moles.

Answer 2

Answer:

4 mols

Explanation:

Step 1: Find molar mass of AgCl

Ag - 107.8682

Cl - 35.45

Ag + Cl = 143.318 g/mol

Step 2: Conversion

$573.26g AgCl (\frac{1 mol}{143.318 g})$

We should get 4.00005, rounded to 4 mols as our answer.