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34kurt
3 years ago
5

Use the Earth's Energy Budget diagram to answer the question. Based on the diagram, less solar energy that reaches Earth is ____

_ than is _____.
A.


reflected, radiated


B.


absorbed, reflected


C.


absorbed, radiated


D.


radiated, reflected
Chemistry
1 answer:
Ivan3 years ago
5 0
<span>absorbed, radiated
Hope this helps. </span>
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<h2><u><em>It's malleability</em></u> Is what makes wax good for making molds </h2>
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4 years ago
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Three nails have a mass of 3.05 g. How many moles of iron do they contain?
serg [7]

Hello!

Three nails have a mass of 3.05 g. How many moles of iron do they contain?

Data:

3 nails of iron = 3.05 g (by nail)  

The atomic mass of iron is 55.845 amu, so the molar mass is:

M = 55.845 → M ≈ 56 g / mol    

With a simple 3 rule:  

56 g → 1 mol

3.05 g → y mol  

Therefore:

\dfrac{56}{3.05} = \frac{1}{y}

56*y = 1*3.05

56y = 3.05

y = \dfrac{3.05}{56}

\boxed{y \approx 0.05446\:mol}}

Soon:

3 nails → 3*0.05446 = 0.1638 moles (answer)

_______________________

I Hope this helps, greetings ... Dexteright02! =)

5 0
3 years ago
if 0.953 g of copper was actually recovered at the end of the entire experiment, what would be the percent yield?
GrogVix [38]

Here is the full question:

Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)

1.000 g copper wire is reacted with 10 mL of concentrated nitric acid (16M). If 0.953 g of copper was actually recovered at the end of the entire experiment, what would be the percent yield?

Answer:

95.30 %

Explanation:

equation for the reaction is given as:

Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)

1.00 g of Cu = \frac{1.00}{63.54 mol of Cu}

= 0.01574 mol of Cu

10 mL of 16 M HNO3 = 10*\frac{16}{1000 mole of HNO3}

= 0.16 mol of HNO3

However, from both variables; we can arrive at a conclusion that Cu is the limiting reagent.

therefore % yield = = 4.70 %

Percentage yield = \frac{actual yield}{theorectical yield} *100%

Percentage yield = \frac{0.953}{ 1.000}* 100%

Percentage yield = 0.953 × 100%

Percentage yield = 95.30 %

3 0
3 years ago
effect. RbClO(s) → Rb+(aq) + ClO−(aq) HClO(aq) + H2O(l) equilibrium reaction arrow H3O+(aq) + ClO−(aq) The degree of dissociatio
Lemur [1.5K]

Explanation:

Common ion effect is defined as the effect which occurs on equilibrium when a common ion (an ion which is already present in the solution) is added to a solution. This effect generally decreases the solubility of a solute.

Equilibrium reaction of strontium sulfate and sodium sulfate follows the equation:

RbClO(s)\rightarrow Rb^{+}(aq.)+ClO^{-}(aq.)

HClO(aq)+H_2O\rightleftharpoons H_3O^+(aq.)+ClO^{-}(aq.)

According to Le-Chateliers principle: If there is any change in the variables of the reaction, the equilibrium will shift in the direction in order to minimize the effect.

In the equilibrium reactions, hypochlorite ion is getting increased on the product side, so the equilibrium will shift in the direction to minimize this effect, which is in the direction of hydrogen hypochlorite.

Thus, the addition hypochlorite ions will shift the equilibrium in the left direction.

The dissociation of hydrogen hypochlorite is suppressed due to the common ion effect.

8 0
4 years ago
I’m boreddd…………………..
meriva

Answer:

im also BOREDDDDDDDDDDDD.....

7 0
3 years ago
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