Answer:
d.) belong to the same family of elements
Explanation:
All atoms of elements present in same group having same number of valance electrons. Thus the elements in same group having same properties.
For example:
Consider the second group. It consist of alkaline earth metals. There are six elements in second group. Beryllium, magnesium, calcium, strontium, barium and radium.
All have two valance electrons.
Electronic configuration of Beryllium:
Be = [He] 2s²
Electronic configuration of magnesium.
Mg = [Ne] 3s²
Electronic configuration of calcium.
Ca = [Ar] 4s²
Electronic configuration of strontium.
Sr = [Kr] 5s²
Electronic configuration of barium.
Ba = [Xe] 6s²
Electronic configuration of radium.
Ra = [ Rn] 7s²
Answer:
+4
Explanation:
The oxidation number of C in carbon dioxide (CO2) is (rules 1 & 2): 0 + (2 x 2) = +4 [Check (rule 3): +4 + 2(-2) = 0] The oxidation number of C in methane (CH4) is (rules 1 & 2): 0 – (4 x1) = -4 [Check (rule 3): -4 + 4(-1) = 0].
Trees are a renewable resource that can be used as an energy source.
Answer: 0.5 atm
Explanation:
you would want to use Boyles law which is P1P2=P2V2
or in this case, 1.00atm x 5.00L=P2 x 10.0L
1.00x5.00/10.00= 0.50atm
Answer:
72.0 mL of steam is formed.
Explanation:
The reaction is :
You can treat coefficient of compounds as amount of volume used.
Therefore for 4 mL of ammonia 5 mL of oxygen is used to form 4 mL of nitric oxide gas and 6 mL of steam.
For 1 mL of ammonia 
(=1.25) mL of oxygen is used to form 
(=1) mL of nitric oxide gas and 
(=1.5) mL of steam.
OR
Just transform the chemical equation by dividing the whole equation by 4 so that the coefficient of 
become one like this
We don't know which one will be completely exhausted and which one will be left so we have to consider two cases :
<em>1. </em><em>Assume ammonia to be completely exhausted</em>
For 50 mL of ammonia 
(= 62.5) mL of oxygen is needed. But we have just 60 mL of oxygen so this assumption is false.
2. <em>Assume oxygen to be completely exhausted</em>
For 60 mL of oxygen only 
(=48) mL of ammonia is needed. In this case we have sufficient amount of ammonia. So this case is true.
Now we know that during complete reaction 48 mL of ammonia and 60 mL of oxygen is used which will form (= 48) mL of nitic oxide gas and 
(= 72) mL of steam.
Therefore <em>72 mL of steam </em>is formed.
