There is a 60 minute gap between the two clocks.
These 60 minutes result of a 1 min advance in one for each hour and a 2 min loss in the other.
if we are going 2 mins back and 1 min in
We have a 3 min gap/hour
then to reach a 1 hour gap we would need to go for 2+1+2+1+2+1+2....(20 hours)
since each 3 represent an hour,
to get 60 min gap>60/3=20 hours
Take clock 1 for example, which read 12:00, in reality the time is (12:00-20 minutes)=11:40
or
Take clock 2 for example, which read 11:00, in reality the time is (11:00+20×2 minutes)=11:40
Now go back 20 hours from that;
11:40-20=00:40-9=15:40
There's ur answer 15:40 :)
Answer:
Step-by-step explanation:
x+1· x+2=7
Simplify x+1· x+2: 2x+2x+1· x+2
Add similar elements: x+1· x=2x=2x+2
2x+2=7[ 2x+2=7 ]
Isolate x for 2x+2=7: x=52 2x+2=7
Subtract 2 from both sides
2x+2−2=7−2
Simplify
2x=5
Divide both sides by 2
2x2 =52 Simplify
Answer:
80 cm / 180 cm / 120 cm
Step-by-step explanation:
the smallest common multiple of 3, 4 and 2 is 12.
so, to be able to truly compare these fractions we need to bring all denominators to .../12.
1/3 = 4/12
3/4 = 9/12
1/2 = 6/12
in total we have therefore 19 (4+9+6) equally large parts of the ribbon that are then combined :
4 parts for the first segment.
9 parts for the second segment
6 parts for the third segment.
so, one part is
380 cm / 19 = 20 cm
therefore the first segment of the ribbon is
4×20 = 80 cm long
the second segment
9×20 = 180 cm long
the third segment
6×20 = 120 cm long
Answer:
$48
Step-by-step explanation:
16 x 3 = 48
Hey there, the answer is C.
After multiplying, you will get .37278. However, it's asking you to consider the significant figure of 3 so you'll have to round it to .373. C has that only option
