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OLEGan [10]
3 years ago
11

James Proton prepares a saturated solution of sodium chloride in a beaker by adding solid sodium chloride and stirring. When Jam

es finishes, crystals of sodium chloride are observed at the bottom of the beaker. Which statement is true regarding the solution?
A. The concentration of sodium ions is constantly changing.
B. The concentration of chloride ions is constantly changing.
C. Solid sodium chloride never dissolves to form sodium ions and chloride ions.
D. Sodium ions and chloride ions collide and combine to form solid sodium chloride.
Chemistry
1 answer:
Snezhnost [94]3 years ago
4 0

Your answer is choice C. That is solid sodium chloride never dissolves to form sodium ions and chloride ions.

Going further to explain, have a look at the question again, we are told that James Proton prepares a saturated solution of sodium chloride in a beaker by adding solid sodium chloride and stirring.

Then when James finishes, crystals of sodium chloride are observed at the bottom of the beaker.

This implies that no more salt was dissolving since the saturation point was reached.

Again suppose he increased the temperature of the reaction, more salts could have dissolved.

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5Br−+BrO3−+6H+→3Br2+3H2O
sashaice [31]

Explanation :

The balanced chemical reaction is,

5Br^-+BrO_3^-+6H^+\rightarrow 3Br_2+3H_2O

The expression for the rates of consumption of the reactants are:

The rate of consumption of Br^- = -\frac{1}{5}\frac{d[Br^-]}{dt}

The rate of consumption of BrO_3^- = -\frac{d[BrO_3^-]}{dt}

The rate of consumption of H^+ = \frac{1}{6}\frac{d[H^+]}{dt}

The expression for the rates of formation of the products are:

The rate of consumption of Br_2 = +\frac{1}{3}\frac{d[Br_2]}{dt}

The rate of consumption of H_2O = +\frac{1}{3}\frac{d[H_2O]}{dt}

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3 years ago
1. A 25 g rock is placed in a graduated cylinder with water. The volume of the liquid rises from 18.3 mL to 21.4 mL Calculate th
MaRussiya [10]

Answer:

1. \rho=8.06g/cm^3

2. H=10cm

Explanation:

Hello,

1. In this case, since the volume of the rock is obtained via the difference between the volume of the cylinder with the water and the rock and the volume of the cylinder with the water only:

V=21.4mL-18.3mL=3.1mL

Thus, the density turns out:

\rho=\frac{m}{V}=\frac{25g}{3.1cm^3}  \\\\\rho=8.06g/cm^3

2. In this case, given the density and mass of aluminum we can compute its volume as follows:

V=\frac{m}{\rho}=\frac{1080g}{2.7g/cm^3}=400cm^3

Moreover, as the volume is also defined in terms of width, height and length:

V=W*H*L

The height is computed to be:

H=\frac{V}{L*W}=\frac{400cm^3}{5cm*8cm}\\ \\H=10cm

Best regards.

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