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Rudiy27
4 years ago
7

Scoring: Your score will be based on the number of correct matches minus the number of incorrect matches. There is no penalty fo

r missing matches. Use the References to access important values if needed for this question. Indicate whether each of the following compounds will gave an acidic, basic or neutral solution when dissolved in water.
ammonium perchlorate
sodium fluoride
calcium chloride
calcium nitrate
The pH will be less than 7.
The pH will be approximately equal to 7.
The pH will be greater than 7.
Chemistry
1 answer:
bonufazy [111]4 years ago
5 0

Answer:

- Ammonium perchlorate: acidic, so its pH will be less than 7.

- Sodium fluoride: basic, so its pH will be greater than 7.

- Calcium chloride: neutral, so its pH will be approximately equal to 7.

- Calcium nitrate: neutral, so its pH will be approximately equal to 7.

Explanation:

Hello,

In this case, we can foresee whether the given bases are acidic, neutral or basic by knowing both the acid and base they come from. In such a way, if a strong acid reacts with a strong base, the resulting salt is neutral, next, if a strong acid reacts with a weak base the resulting salt is acidic and if a weak acid reacts with a strong base the resulting salt is basic. Therefore, we have:

- Ammonium perchlorate: it comes from ammonium hydroxide or ammonia that are weak bases and perchloric acid which is a strong acid, therefore the salt is acidic so its pH will be less than 7.

- Sodium fluoride: is comes from sodium hydroxide which is a strong base and hydrofluoric acid which is a weak acid, therefore the salt is basic so its pH will be greater than 7.

- Calcium chloride: it comes from calcium hydroxide and hydrochloric acid which are both strong, for that reason the resulting salt will be neutral so its pH will be approximately equal to 7.

- Calcium nitrate: it comes from calcium hydroxide and nitric acid which are both strong, for that reason the resulting salt will be neutral so its pH will be approximately equal to 7.

Best regards.

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PbI(ii) ionization in the solution of PBI(ii) into water is:

<span>PbI</span>₂(solution) <==> Pb₂⁺ + 2I⁻

If the conc. of PbI(ii) in the sol. is xM then the conc. of Lead(ii) will be x M and conc. of iodide will be 2 x M.

Therefore,

<span>Ksp=<span>[Pb</span></span>²⁺][I-]²

Plugging the values:

1.4×10⁻⁸ = x ⋅ (2x)²

1.4×10⁻⁸ = 4x³

x³ = {1.4×10⁻⁸}÷4

x³ = 0.35 x 10⁻⁸

or 

x³ = 3.5 x 10⁻⁹

x = 1.51 x 10⁻³

Hence,

Concentration of iodide ions in the solution:

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3 years ago
Calculate the density of a block of water measuring 2 cm x 4 cm x 1 cm, with a mass of 5.4
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the formula for density is p=m/v

m aka the mass = 5.4; the v aka the volume = 8

so, p=5.4/8

p= 0.675 g/cm^3

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3 years ago
How much work is done on a pumpkin with a force of 16 newtons when you lift is 15 meters?
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Answer:

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ly/3fcEdSx

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3 years ago
A. Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculat
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Answer:

A)Mass of  gallium plated out is 0.3440 grams

B) For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

Explanation:

To calculate the total charge, we use the equation:

C=I\times t

where,

C = Charge

I = Current in time t (seconds)

To calculate the moles of electrons, we use the equation:

\text{Moles of electrons}=\frac{C}{F}

where,

F = Faraday's constant = 96500

A) The equation for the deposition of Ga(s) from Ga(III) solution follows:

Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)

I = 0.790 A, t = 30.0 min = 1800 seconds

C=I\times t

C=0.790 A\times 1800 s=1422 C

Moles of electron transferred:

=\frac{1422 C}{96500 F}=0.01474 mol

Now, to calculate the moles of gallium, we use the equation:

\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}

n = number of electrons transferred = 3

\text{Moles of Gallium}=\frac{0.01474 mol}{3}=0.004913 mol

Mass of 0.004913 moles of gallium = 0.004913 mol × 70 g/mol=0.3440 g

B) The equation for the deposition of Sn(s) from Sn(II) solution follows:

Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)

Moles of tin = \frac{8.70 g}{119 g/mol}=0.07311 mol

n = number of electrons transferred = 2

\text{Moles of tin}=\frac{\text{Moles of electrons}}{n}

Moles of electron =  n\times \text{Moles of tin}

=2\times 0.07311 mol=0.14622 mol

Charge transferred during time t :

\text{Moles of electrons}=\frac{C}{F}

C=96500 F\times 0.14622 mol=14,110.23 C

Current applied for t time = I = 5.79 A

t=\frac{C}{I}=\frac{14,110.23 C}{5.79 A}=2,437 s=0.67 hrs

For 0.67 hours current of 5.79 A must to be applied to plate out 8.70 g of tin.

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4 years ago
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Dmitry_Shevchenko [17]

The total pressure  1566 mm Hg.

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The SI unit of stress is pascal which is identical to one newton in keeping with rectangular meter. apparently, this name was given in 1971. earlier than that pressure in SI became measured in newtons in line with square meter.

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=> 1.2 atm = 1.2 * 760 mm Hg

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S0, Total pressure = Par + P ne + P he

                              =  ( 429 + 912 + 225 ) mm Hg

                              = 1566 mm Hg

Learn more about pressure here:-brainly.com/question/25965960

#SPJ4

6 0
1 year ago
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