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3 years ago

D=420-65t what is the d-intercept

1 answer:

7 0

<span>d=420-65t. Geometric figure: Straight Line. Slope = -0.031/2.000 = -0.015; d-intercept = 420/1 = 420.00000; t-intercept = 420/65 = 84/13 = 6.46154. Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : d-(420-65*t)=0.</span>

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What is the slope of this graph

telo118 [61]

Answer: positive I think

Step-by-step explanation:

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2 years ago

Noam walks home from school by walking 8 blocks north and then 6 blocks east. how much shorter would his walk be if there were a

nalin [4]

The distance he travels is 6+8=14 blocks. the straight line distance is the hypotenuse of a right triangle with legs 8 and 6.
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3 0

3 years ago

Read 2 more answers

The units digit of a two-digit exceeds twice the tens digit by 3. The sum of the digits is 6. Find the number

tekilochka [14]

Answer:

Step-by-step explanation:

y is the ten digit

and x the ones digit

y+x=6 -> x=6-y subtracted each side by y

2y+3=x

2y+3=6-y they both equal x so the equal each other

add y to both side to get rid of the y

minus 3 form both side to get rid of the 3

3y=3

y=1

plug it in

2(1)+3=x

5=x

8 0

3 years ago

Students at an elementary school attended school five days each week after three weeks of attendance each student has attended s

lukranit [14]

Answer:

for 6300 minutes they have to come to school for 1260 days and if you mean 63 they have to come 12.6 days

Step-by-step explanation:

7 0

2 years ago

Researchers at a lake have determined that the percentage of fish in the lake that are intolerant to pollution can be estimated

dusya [7]

Answer:

a. 23.02 %

b. 49%

c. W

Step-by-step explanation:

Solution:-

- A multi-variable function for the percentage of fish in the lake that are intolerant to the pollution is given as:

$P ( W , R , A ) = 49 - 1.61W - 1.41R - 1.38A$

Where,

W: percentage of wetland

R: percentage of residential area

A: percentage of agriculture

- We are to evaluate the percentage of fish intolerant to pollution in the case where W = 3 , R = 15 , A = 0. We will plug in the values in the modeled function P ( W , R , A ) as follows:

$P ( 3 , 15 , 0 ) = 49 - 1.61*3 - 1.41*15 -1.38*0\\\\P ( 3 , 15 , 0 ) = 23.02\\$

- To determine the maximum percentage of fish that will be intolerant to pollution we will employ the use of critical points. The critical point that is defined by the linear relationship between P and all other parameters ( W, R , A ). The maximum value occurs when W = R = A = 0.

$P ( 0 , 0 , 0 ) = 49 - 1.61*0 -1.41*0 - 1.38*0 = 49$

- Hence, the maximum value of the function is 49%.

- The linear relationship between each induvidual parameter ( R, W , A ) and the function ( P ) is proportional in influence. The extent of influence can be quantized by the constant multiplied by each parameter.

- We see that that ( 1.61*W ) > ( 1.41R ) > ( 1.38A ). The greatest influence is by parameter ( W ) i.e the influence of percentage of wetlands .

6 0

3 years ago