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Triss [41]
3 years ago
8

Write an equation of the line that contains point (-5,2) and is parallel to the y-axis

Mathematics
1 answer:
lutik1710 [3]3 years ago
5 0

Answer: x = -5 (rewritten: x + 5 = 0)

Step-by-step explanation:

First, we must take into account that the line is parallel to the y-axis. If a line is parallel to the y-axis, it is vertical, meaning that for every y-value, there can only be one x-value. Since the question contains a point that the line passes through, which is (-5, 2), we know that for every y-value of the line, the x-value will always equal -5. Thus, the equation of the line must be x = -5 (or, rewritten, x + 5 = 0).

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Am i doing this right????
Anna35 [415]
You are going in the right direction. For the distance of ST I get √136
√(-5-1)² + (6+4)² =
√(-6)² + (10²) =
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√34² + √136² =√170²
34 + 136 = 170
170 = 170
3 0
3 years ago
Which of the following could be the equation of the graph shown below? Check all that apply.
Mashutka [201]

Answer:

y = -2x + 5

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8 0
3 years ago
The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2x + 6. What is the
matrenka [14]

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Step-by-step explanation:

See attached image, it's direct formula substitution.

3 0
2 years ago
WILL GIVE BRAINLIEST TO CORRECT ANSWER(S)
elena55 [62]

Answer:

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Step-by-step explanation:

Hopefully this helped!!!

7 0
3 years ago
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enot [183]

Answer:

3

Step-by-step explanation:

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7 0
3 years ago
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