The answer would be A = 54raiz (3) + 18raiz (91)
Formula:
A = Ab + Al Where, Ab=base area A= lateral area
The area of the base is: Ab = (3/2) * (L ^ 2) * (root (3)) Where, L= side of the hexagon. Substitute: Ab = (3/2) * (6 ^ 2) * (root (3)) Ab = (3/2) * (36) * (root (3)) Ab = 54raiz (3)
The lateral area is: Al = (6) * (1/2) * (b) * (h) Where, b= base of the triangle h= height of the triangle Substitute: Al = (6) * (1/2) * (6) * (root ((8) ^ 2 + ((root (3) / 2) * (6)) ^ 2)) Al = 18 * (root (64 + 27)) Al = 18raiz (91)
The total area is: A = 54raiz (3) + 18raiz (91)
<h3>
Answer: 1848 cubic meters</h3>
=================================================================
Explanation:
Imagine rotating the figure so that the triangular face is flat on the ground. This makes the triangular faces to be the floor and ceiling of this room.
The floor is a triangle with base 24 meters and height 7 meters. The floor area is base*height/2 = 24*7/2 = 84 square meters.
Multiply this floor area with the height of the room (22 m) to get the volume of the room.
volume = (floor area)*(height) = 84*22 = 1848 cubic meters
Answer:
89m
Step-by-step explanation:
First, find the area of the rectangle (ignoring the missing triangle inside). The area of the rectangle is its base times its height, which is 8*13=104.
Next, find the area of the triangle. The area of the triangle is its base times height, divided by two.
The width of one side of the rectangle is 13, and the width of the side of the rectangle is 8 (4 + 4). Therefore, subtract 8 from 13 and the missing section in the side of the rectangle is 5. 5 is equal to the base of the triangle.
The height of the triangle is given, which is 6. As stated before, the area of a triangle is its base times height divided by two, which is 5*6/2 in this case. The area of the triangle is equal to 15.
Now, subtract the area of the triangle from the area of the rectangle. 104-15=89.
Lengths are given to 1dp so the biggest that the lengths could be is 4.65cm and 5.35cm. if you use pythagoras on these to find hypotenuse, this is the upper bound.
Is is b I am sure that is the right