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slamgirl [31]
3 years ago
9

If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK

Mathematics
1 answer:
Gala2k [10]3 years ago
4 0

Answer:

The value of mHLK will be "(204)°".

Step-by-step explanation:

The given values are:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

mHLK = ?

Now,

By using chord-chord formula of angle, we get

mHMK=\frac{1}{2}(mJL+mHLK)

On putting the values in the above formula, we get

⇒  (8x-1)=\frac{1}{2}(15x-36+3x+2)

On applying cross-multiplication, we get

⇒  2(8x-1)=18x-34

⇒  16x-2=18x-34

On subtracting "18x" from both sides, we get

⇒  16x-2-18x=18x-34-18x

⇒  -2x-2=-34

On adding "2" both sides, we get

⇒  -2x=-34+2

⇒  -2x=-32

⇒  x=\frac{32}{2}

⇒  x=16

On putting the value of "x" in mHLK = (15x-36)°, we get

⇒ (15x-36)° = (15×16-36)°

⇒                = (240-36)°

⇒                = (204)°

So that mHLK = (204)°

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  3. Exponents
  4. Multiplication
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Step-by-step explanation:

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  1. Substitute [PT]:                    8² + 8² = x²
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  3. Add:                                      128 = x²
  4. Isolate <em>x</em>:                               8√2 = x
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