Priya’s cat weights 5 1/2 pounds and her dog weighs 8 1/4 pounds. How many times as heavy is the dog than the cat?

4[1 2 -1 5]<br> Someone help me with this bs

natulia [17]

Answer:

<u>-12</u>

Step-by-step explanation:

12 - 15 = -3

4 ( -3 )

= -12

7 0

2 years ago

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Ira described the data on a dot plot as having a cluster from 0 to 3, a gap at 4, a peak at 1, and being skewed right. Which dot

rjkz [21]

Answer:

it would be a

Step-by-step explanation:

5 0

3 years ago

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An HMO pamphlet contains the following recommended weight for women: "Give yourself 100 pounds for the first 5 feet plus 5 pound

fenix001 [56]

Answer: 5 feet and 7 inches

Step-by-step explanation:

"Give yourself 100 pounds for the first 5 feet plus 5 pounds for every inch over 5 feet tall"

100 pounds for 5 feet + 5 pounds/inch [over 5 feet]

We can separate 135 pounds into two parts: the first 100 pounds and the other 35 pounds: 135 = 100 + 35

100 = 5 feet

35 pounds/5 pounds/inch = 7 inches

So, the height is 5 feet and 7 inches

7 0

3 years ago

A triangle has a right angle and an acute angle of 51 degree's and X. What is X? (Number Only)

Diano4ka-milaya [45]

Answer:

39°

sum of triangle's interior angles: 180°

180°-90°-51°=39°

6 0

3 years ago

let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)

statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

$\sin (\theta)=\frac{3}{5}$

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

$x^2+3^2=5^2$

Solving for x, we have

$\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}$

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

$\tan (y)=\frac{12}{5}$

Describes the following triangle

Using the Pythagorean Theorem again, we have

$5^2+12^2=h^2$

Solving for h, we have

$\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}$

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

$\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}$

To calculate the sine and cosine of the sum

$\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}$

We can use the following identities

$\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}$

Using those identities in our problem, we're going to have

$\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}$

4 0

1 year ago