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Ilia_Sergeevich [38]
3 years ago
6

Priya’s cat weights 5 1/2 pounds and her dog weighs 8 1/4 pounds. How many times as heavy is the dog than the cat?

Mathematics
1 answer:
Margaret [11]3 years ago
7 0

Answer:

Step-by-step explanation:

2 3/4

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Use the following table for questions 11-13.A baseball manager believes a linear relationship exists between the number of Home
slamgirl [31]

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Y-\bar{Y}=b_{yx}(X-\bar{X})

Where byx is given by the formula:

b_{yx}=\frac{N\sum^{}_{}XY-\sum^{}_{}X\sum^{}_{}Y}{N\sum^{}_{}X^2-(\sum^{}_{}X)^2}

Where N is the number of values (N=8). We need to find the sum of X values, the sum of Y values, the average of X, the average of Y, the sum of X*Y and the sum of X^2.

The table of values is:

The values we need to know are on the following table:

By replacing the known values in the formula we obtain:

\begin{gathered} b_{yx}=\frac{8\cdot26125-167\cdot995}{8\cdot4649-(167)^2} \\ b_{yx}=\frac{209000-166165}{37192-27889} \\ b_{yx}=\frac{42835}{9303} \\ b_{yx}=4.6 \end{gathered}

Now, the average of X and Y is the sum divided by N, then:

\begin{gathered} \bar{X}=\frac{167}{8}=20.87 \\ \bar{Y}=\frac{995}{8}=124.37 \end{gathered}

Replace these values in the formula and find the regression equation as follows:

\begin{gathered} Y-124.37=4.6(X-20.87) \\ Y-124.37=4.6X-4.6\cdot20.87 \\ Y=4.6X-96.11+124.37 \\ Y=4.6X+28.26 \end{gathered}

The answer is a) y=4.6x+28.26

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1 year ago
Help me please<br>help me please​
Nikolay [14]

Answer:

1 second

Step-by-step explanation:

s=-5\\u=0\\v=\\a=-10\\t=t

\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac12at^2\\ \implies -5 & =(0)t+\dfrac12(-10)t^2\\ -5 & = -5t^2\\ t^2& = 1\\ t & = \pm\sqrt{1}\\ t & = 1\: \sf s\end{aligned}

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Shtirlitz [24]

<span>What is the area of a regular octagon with a side length of 4.6 meters and a length from the center to a vertex of 6 meters? 

Good Morning
 
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