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Marysya12 [62]
3 years ago
11

One argument against the American standard system of measurement is a lesser degree of accuracy than that of the metric system.

Explain how the standard side of a ruler with inches broken down to 1/16th of an inch would have less accuracy than the metric side of the same ruler with each centimeter broken down to millimeters?
Mathematics
2 answers:
densk [106]3 years ago
5 0
In this item, we are to divide one (1) inch into 16 equal parts to be able to conclude that American standard system is less accurate than the metric system. 
         16 parts of 1 inch = 1 inch / 16 = 0.0625 inch

This in itself is already a proof enough that there are 4 decimal places after the decimal point which makes this hard to properly measure.

Whereas, if we are to divide a centimeter into the millimeters, we will have 10 equal parts and that would be 1 mm = 0.1 cm.

The number above only has one decimal place and the level of accuracy should be higher. 
Ket [755]3 years ago
4 0
1/16 inches will be 0.0625 inches
1 cm = 10mm or 1mm = 0.1cm

The difference in the 0.0625 and 0.1 is that the 0.0625 will be harder to partition than the 0.1
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Determine whether
lora16 [44]

Answer:

(a) and (b) are not equivalent

(c) is equivalent

Step-by-step explanation:

Given

\frac{25^m}{5}

Required

Determine an equivalent or nonequivalent expression

(a)\ 25^{m-1

We have:

25^{m-1

Apply law of indices

25^{m-1} = \frac{25^m}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

(b)\ 25^{2m - 1}

We have:

25^{2m - 1}

Apply law of indices

25^{2m - 1} = \frac{25^{2m}}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

<em></em>

<em />(c)\ 5^{2m-1}<em />

We have:

<em />5^{2m-1}<em />

Apply law of indices

<em />5^{2m-1} = \frac{5^{2m}}{5^1}<em />

<em />5^{2m-1} = \frac{5^{2m}}{5}<em />

<em>Evaluate the numerator</em>

<em />5^{2m-1} = \frac{25m}{5}<em />

<em />

<em>This is an equivalent expression</em>

4 0
3 years ago
Find the polynomial of lowest degree with only real coefficients and having the given zeros. -7i and square root of 2
mario62 [17]

Answer:

x³ - (√2)x² + 49x - 49√2

Step-by-step explanation:

If one root is -7i, another root must be 7i.  You can't just have one root with i.  The other roos is √2, so there are 3 roots.  

x = -7i       is one root,

   (x + 7i) = 0    is the factor

x = 7i       is one root

  (x - 7i) = 0     is the factor

x = √2      is one root

    (x - √2) = 0   is the factor

So the factors are...

(x + 7i)(x - 7i)(x - √2) = 0

Multiply these out to find the polynomial...

(x + 7i)(x - 7i) =  x² + 7i - 7i - 49i²

Which simplifies to

  x² - 49i²        since i² = -1 , we have

    x² - 49(-1)  

 

      x² + 49

Now we have...

(x² + 49)(x - √2) = 0

Now foil this out...

 x²(x) - x²(-√2) + 49(x) + 49(-√2) = 0

     x³ + (√2)x² + 49x - 49√2

7 0
3 years ago
A rectangular garden has a walk around it of width x. The garden is 20 ft by 15 ft. Write a function representing the combined w
kodGreya [7K]

Answer: A(x) = 15 ft + 2x

 

EXPLANATION

 

Given,

The dimension of the rectangular garden is 20 ft by 15 ft.

Dimension of a rectangle is written as Length by Width

This implies that,

Length of the garden = 20 ft

Width of the garden = 15 ft

 

The garden has a walk around it of width x.

The combined width of the garden = Width of garden + 2x

[we are adding twice the width of the walk because it is around the garden (this means it will add to the width of the garden on both the left and right sides)]

 

Combined width of the garden, A(x) = Width of garden + 2x

Since width of the garden = 15 ft

A(x) = 15 ft + 2x

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Answer:

Sorry to break it to you

Step-by-step explanation:

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8 0
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The Garzas plan to invest $2,000 for 5 years. What annual simple interest rate must the investment earn in order for the Garzas
insens350 [35]

Answer:

r=20%

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=5\ years\\ P=\$2,000\\ A=\$4,000\\r=?

substitute in the formula above

4,000=2,000(1+5r)

solve for r

2=(1+5r)

5r=2-1\\5r=1\\r=\frac{1}{5}=0.20=20\%

8 0
3 years ago
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