What is the area of a rectangle with vertices located at (-1, 1), (-1, - 4), (5. – 4), and (5, 1)?

Mathematics

1 answer:

SOVA2 [1]4 years ago

4 0

Answer:

30 units²

Step-by-step explanation:

Width = 1 - (-4) = 5

Length = 5 - (-1) = 6

Area = 5×6 = 30

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Equation that has a slope of -4 and passes through the point (-2, 2) show work too

Alenkinab [10]

Answer:

y=-4x-6

Step-by-step explanation:

y=mx+b, where m is the slope and b is the y-intercept

Slope is given as -4, so:

y=-4x+b

To find b, sub in the point we were given (-2,2):

2=-4(-2)+b

2=8+b

b=2-8=-6

So we have: y=-4x-6

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3 years ago

the equation of the line a is given as y = -3/4 x -2. Suppose the line a is parallel to line b and lime t is perpendicular to li

Burka [1]

Answer: The equation for line b is $y = -\frac{3}{4}x + 5$

The equation for line t is $y= \frac{4}{3} x+5$

The attachment shows the original line in green, the parallel line b in red, and the perpendicular line t in blue.

Step-by-step explanation: Use slope intercept form, y = mx + b

The given coordinate, (0,5) is on the y-axis, so 5 will be the y-intercept of the equation. Keep the slope of the original equation and substitute the new value for "b"

To write the equation for line t

Both lines share the y-intercept, (0,5) so the "b" term will be the same. The slope of a perpendicular line is the reciprocal of the original slope with the opposite sign.

So invert 3/4 to become 4/3 and change the negative sign to positive.

The resulting equation is y = 4x/3 + 5