Answer:
A. 57.6
Step-by-step explanation:
6 times 5.2 is 31.2. 4 times 5 is 20. 6 times 5 is 30. 6 times 5 is 30. (31.2/2)+(20/2)+30= 55.6 Then you round nearest tenth. 57.6.
We have that
<span>y=2x+4--------> equation 1
3x−6y=3-------> equation 2
step 1
</span>I substitute the value of y in equation 1 for the value of y in equation 2<span>
so
</span>3x−6*[2x+4]=3-------> 3x-12x-24=3
-9x=3+24
-9x=27------> 9x=-27
x=-27/9
x=-3
step 2
<span>I substitute the value of x in equation 1 to get the value of y</span>
y=2x+4--------> y=2*(-3)+4--------> y=-6+4
y=-2
the answer is
the solution is the point (-3,-2)
x=-3
y=-2
yes It has at least one set of parallel lines
Step-by-step explanation:
Since it remains only 1 sweet, we can subtract it from the total and get the amount of sweets distributed (=1024).
As all the sweets are distributed equally, we must divide the number of distributed sweets by all its dividers (excluding 1024 and 1, we'll see later why):
1) 512 => 2 partecipants
2) 256 => 4 partecipants
3) 128 => 8 partecipants
4) 64 => 16 partecipants
5) 32 => 32 partecipants
6) 16 => 64 partecipants
7) 8 => 128 partecipants
9) 4 => 256 partecipants
10) 2 => 512 partecipants
The number on the left represents the number of sweets given to the partecipants, and on the right we have the number of the partecipants. Note that all the numbers on the left are dividers of 1024.
Why excluding 1 and 1024? Because the problem tells us that there remains 1 sweet. If there was 1 sweet for every partecipant, the number of partecipants would be 1025, but that's not possible as there remains 1 sweet. If it was 1024, it wouldn't work as well because the sweets are 1025 and if 1 is not distributed it goes again against the problem that says all sweets are equally distributed.
A) The length of the longer leg is x-1
b) Based on the area, the other leg is 2*30/(x -1). Based on the Pythagorean theorem, the other leg is √(x^2 -(x -1)^2).
c) Equating the two expressions for the shorter leg, we have
.. 60/(x -1) = √(2x -1)
.. 3600/(x -1)^2 = (2x -1)
.. (2x -1)(x^2 -2x +1) = 3600
.. 2x^3 -5x^2 +4x -3601 = 0
d) There is one positive real root, at x=13. A graphical solution works well.
The three sides of the triangle are 5 in, 12 in, 13 in.
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5-12-13 is a well-known Pythagorean triple. It is the next smallest one after 3-4-5.