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Over [174]
3 years ago
7

What is the greatest common factor of 4k, 18k4, and 12?

Mathematics
2 answers:
Semenov [28]3 years ago
5 0
The greatest common factor of 4k, 18k4 and 12 is
4

Finding the GCF of monomials requires inspection of the terms and looking for common factors that would be able to reduce the terms to whole numbers and variables with positive exponents.
Elanso [62]3 years ago
3 0
The answer is 4 no k or anything
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Write 12.9 + 8 using words.
Anna35 [415]
Twelve point nine plus eight equals twenty point nine (12.9 + 8 = 20.9)
Hope this helped :)
7 0
3 years ago
What is the slope of the line passing through the points (1, –5) and (4, 1)?
Naddik [55]
The slope is a 2
here the stpes 
6/3 got 2
y2-ya
x2-x1
then you get 6/3 devide ad that you slope

3 0
3 years ago
PLEASE HELP FOR 48 POINTS PLEASE!<br><br><br><br> show/explain your answer and work
pentagon [3]

Answer:

c  This is the direct variation

Step-by-step explanation:

The equation for direct variation is y= kx

Solving this for k

y/x =k

So y/x must be a constant

a.  9/3 =3

2/7 does not =3  so this is not a direct variation


b 1/2 = .5

-3/6 = -.5

This is not the same so this is not a direct variation


c.  27/9 =3

18/6 =3

9/3 =3

This is a direct variation with a constant of 3


d 5/-7 = -5/7

1/-3 = -1/3

This is not the same so this is not a direct variation

4 0
3 years ago
Read 2 more answers
A number is five less than 3 time another number use x for the variable HURRY
maksim [4K]

Answer:

10,  it's 5 less than 5 times 3

Step-by-step explanation:

8 0
2 years ago
Here are two closed containers and four balls just fit into each container. Each ball has a diameter of 60mm. Which container ha
Studentka2010 [4]

Answer:

Container B has smaller surface area.

Step-by-step explanation:

Given:

Container A

Radius = 60/2 = 30 mm

Height = 4 x 60 = 240 mm

Container B

Length = 120

Width = 120

Height = 60

Computation:

Surface area of container A (Cylinder) = 2πr[h+r]

Surface area of container A (Cylinder) = 2[22/7][60][120+60]

Surface area of container A (Cylinder) = 67,885.70 mm² (Approx)

Surface area of container B (Cuboid) = 2[lb+bh+hl]

Surface area of container B (Cuboid) = 2[(14,400)+(7,200)+(7,200)]

Surface area of container B (Cuboid) = 57,600 mm²

Container B has smaller surface area.

8 0
3 years ago
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