The answer to these blanks are :
1. 6 (m)
2. 1 (s)
3. 0 (m)
4. 4 (s)
Answer:1296 if I’m not wrong please
Step-by-step explanation:
(x-8) ^ 2 = 121
(x-8) = + / - root (121)
x = 8 +/- root (121)
The solutions are:
x1 = 8 + root (121)
x2 = 8 - root (121)
2a ^ 2 = 8a-6
2a ^ 2-8a + 6 = 0
a ^ 2-4a + 3 = 0
(a-1) (a-3) = 0
The solutions are:
a1 = 1
a2 = 3
x ^ 2 + 12x + 36 = 4
x ^ 2 + 12x + 36-4 = 0
x ^ 2 + 12x + 32 = 0
(x + 4) (x + 8) = 0
The solutions are:
x1 = -8
x2 = -4
x ^ 2-x + 30 = 0
x = (- b +/- root (b ^ 2 - 4 * a * c)) / 2 * a
x = (- (- 1) +/- root ((- 1) ^ 2 - 4 * (1) * (30))) / 2 * (1)
x = (1 +/- root (1 - 120))) / 2
x = (1 +/- root (-119))) / 2
x = (1 +/- root (119) * i)) / 2
The solutions are:
x1 = (1 + root (119) * i)) / 2
x2 = (1 - root (119) * i)) / 2
9514 1404 393
Answer:
D. Both functions are decreasing at the same average rate on that interval
Step-by-step explanation:
The dashed lines on the attached graph of the two functions (f in red, g in purple) represent the average rate of change of each function on the interval. The lines are parallel, because the average rate of change is the same for each of the functions on that interval.
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Function f decreases by 60 units from f(0) = 64 to f(4) = 4 on the interval x = [0, 4]. Function g decreases by 60 units from g(0) = 75 to g(4) = 15 on the same interval. The average rate of change is the amount of decrease divided by the interval width. Those values are the same for both functions.
Answer:
Length = 3 cm
Width = 1 cm
Step-by-step explanation:
Let the length of rectangle be l and width of rectangle be w.
According to problem,
l = 3w {Length of rectangle is equal to triple the width}
And Perimeter,P = 8 cm
Since, P = 2 ( l + w )
or 8 = 2( l + w)
Plug l =3w in the above perimeter equation.
We get:
8 = 2( 3w + w)
8 = 2(4w)
8 = 8w
or w = 1 cm
Then length ,l = 3w =3 * 1 = 3 cm
Hence length of rectangle is 3cm and width of rectangle is 1cm.
