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Karolina [17]
3 years ago
5

Where does each answer belong in the boxes?? Right answers only, help please!! :))

Mathematics
1 answer:
boyakko [2]3 years ago
7 0

Answer:

Box 1: Quadrant I

Box 2: Quadrant II

Box 3: Quadrant III

Hope this helps.

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Sara has 24 marbles, Mark has 36 marbles, Josh has 22 marbles and Sam has 42 marbles. Everyone packaged their marbles into as ma
Wittaler [7]
Josh will because 22 isn't a multiple of 6
6: 6, 12,18,24,30,36,42
You see 22 isn't here
So Josh will have left over.
~JZ
Hope it helps
5 0
3 years ago
At the city museum, child admission is $5.60 and adult admission is $9.20. On Sunday, 145 tickets were sold for a total sales of
Studentka2010 [4]
Let x be the number of child admission tickets sold:
Child's ticket = x

There is a total of 145 tickets sold:
Adult = 145 - x

Total sales is $1020.80:
5.6x + 9.2(145 - x) = 1020.8

Solve for x:
5.6x + 9.2(145 - x) = 1020.8
5.6x + 1334 - 9.2x = 1020.8
3.6x = 313.2
x = 313.2 ÷ 3.6
x= 87

Answer: Number of child's ticket = 87



5 0
4 years ago
Read 2 more answers
At the first meeting of the Tennis Club, the 7 members decided to have a tournament in which every player will play a match agai
mariarad [96]

Answer:

21 matches

Step-by-step explanation:

This is a combination problem where we have to select two member out of 7 members

 

So we want calculation of  7C2

 

   7C2 = 7!/[(2!)(7-2)!]

   (7*6*5*4*3*2*1)/[(2*1) *(5*4*3*2*1]

   (7*6)/2    ~  Note everything that easily cancels here!

   42/2

   21 matches

5 0
3 years ago
the ratio of chaperones to students a field trip is 1 to 9 if 81 students on the trip how many chaperones were there
kati45 [8]
In the given question it is important to take note of every minute details that are given in the question. using these details the answer to the given question can be easily reached.
Let us assume the common ratio to be x.
Then
x + 9x = 81
10x = 81
x = 81/10
  = 8.1
A s we already know that the ratio of chaperones to students is 1:9
Then
The number of chaperones = 1 * 8.1
                                             = 8.1
So 8.1 chaperones were there in total. I hope you have got the answer you were looking for.
4 0
3 years ago
In a study of government financial aid for college​ students, it becomes necessary to estimate the percentage of​ full-time coll
oksano4ka [1.4K]
The sample size needed to estimate the population proportion of a data within a margin of error, M, to a confidence level of 1 - α, with a previous population proportion estimate, p, is given by:

n=p(1-p)\left( \frac{z_{\alpha/2}}{M} \right)^2

Part A:

Given<span> a margin of error of 0.03 a confidence level of 95​%. Since we have know prior knowledge of the proportion estimate, we make use of the consevartive proportion estimate of 50% or 0.05.

z_{\alpha/2} for 95% confidence is 1.96.

Therefore, the required sample size is given by

n=0.5(1-0.5)\left( \frac{1.96}{0.03} \right)^2 \\  \\ =0.5(0.5)(65.33)^2=0.25(4,268) \\  \\ =1,067.11

Therefore, the required sample size is 1,068.



Part B:

Given that </span><span>prior studies have shown that about 55% <span>of​ full-time students earn​ bachelor's degrees in four years or less.</span></span>

Thus, p becomes 55% = 0.55 and the required sample size is given by

n=0.55(1-0.55)\left( \frac{1.96}{0.03} \right)^2 \\ \\ =0.55(0.45)(65.33)^2=0.2475(4,268) \\ \\ =1,056.44

<span>Therefore, the required sample size is 1,057.</span>



Part C:

When we dont know the additional infromation (i.e. in part A), we obtained that the required sample size is 1,068 but after we know the information our sample size becomes 1,057.

Though there is a difference between both sample sizes but the difference is not much and hence, the knowledge of the additional information does not have much of an effect on the sample size.

6 0
3 years ago
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