He collected $264.00, $72.00 went to his homeroom, and $192.00 to the school
Answer:
Parallel means that the lines will never cross. If we look at a traditional trapezoid, the top side and the bottom side are straight lines that will never cross one another. The left and right sides are slanted towards one another, to they are not parallel.
Hope this helped. : )
0.0239 x 28 = .6692 (this is the amount of tax paid)
shoes + tax = total
$28 + 0.6692 = $28.6692 which rounds to $28.67 (money is always rounded to the hundredths place)
Answer:
![A=900(1+\frac{0.06}{2})^{2(t)}](https://tex.z-dn.net/?f=A%3D900%281%2B%5Cfrac%7B0.06%7D%7B2%7D%29%5E%7B2%28t%29%7D)
Step-by-step explanation:
Lets use the compound interest formula provided to solve this:
![A=P(1+\frac{r}{n} )^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bnt%7D)
<em>P = initial balance</em>
<em>r = interest rate (decimal)</em>
<em>n = number of times compounded annually</em>
<em>t = time</em>
First, change 6% into a decimal:
6% ->
-> 0.06
Since the interest is compounded semi-annually, we will use 2 for n. Lets plug in the values now and your equation will be:
![A=900(1+\frac{0.06}{2})^{2(t)}](https://tex.z-dn.net/?f=A%3D900%281%2B%5Cfrac%7B0.06%7D%7B2%7D%29%5E%7B2%28t%29%7D)
Answer:
495 meter²
Step-by-step explanation:
In the given kite QRST,
PQ = PS = 15 meter
QR = 17 meter
We have to find the area of the kite.
Since kite is in the form of a rhombus.
and rhombus is =
(Diagonal QS) × (Diagonal RT)
In Δ QRP,
17² = 15² + RP²
![\sqrt{17^{2}-15^{2}} = RP](https://tex.z-dn.net/?f=%5Csqrt%7B17%5E%7B2%7D-15%5E%7B2%7D%7D%20%3D%20RP)
= √64 = 8 meters.
So RT = RP + PT = 8 + 25 = 33 meter.
Now area of kite =
(30) (33) = 495 meter²