Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
25 Lol
Step-by-step explanation:
Answer:
Thank you so much. She has even deleted one of my questions before. I'll take care and beware.
J = K = 45° or 315°
...........................................................
Answer:
The perimeter of the quarter-circle is 200 cm.
Step-by-step explanation:
Given that the angle of quarter-circle is 90°. So using Length of Arc formula, you are able to find the length of curve :
Let r be radius = 56 cm,
Let θ = 90°
We have already found the arc. Next we have to add up together to find the perimeter :
