Answer:
B
Step-by-step explanation: Because for inverse functions, domain and range of functions exchange. In simple words, domain of function h(x) = range of inverse function & range of function h(x) = domain of inverse function.
F(X) = (3x + 5)/X
F(a + 2) = (3(a + 2) + 5)/(a + 2)
F(a + 2) = (3a + 6 + 5)/(a+2)
F(a + 2) = (3a + 11)/(a + 2).
This would be the final solution.
ANSWER
My answer is in the photo above
Answer:
Assume that Sn is valid for n = k and prove that Sn is valid for n = k + 1.
Step-by-step explanation:
This is the second step in the principal of mathematical induction. The three steps in the principals of mathematical induction are:
1. show that something works for the first case (base or anchor step)
2. assume that it works for any particular step (inductive hypothesis), and then
3. show that it works for the next case (inductive step)
p. 621 in textbook
It's weird that they put steps 2 & 3 together, but it was correct on the test so ¯\_(ツ)_/¯
D
just subtract 14 from 26