Answer:
cos(C)
Step-by-step explanation:
Recall that the sine ratio is opposite over hypotenuse.
Also the cosine ratio is adjacent over hypotenuse.
The tangent ratio does not come close because it doesn't involve the Hypotenuse.
The total area available for cars to park will be 858m².
<h3>How to calculate the area?</h3>
The area of the parking lot will be:
= 78 × 19
= 1482m²
The area of aisle will be:
= 8 × 78
= 624m²
The available area will be:
= 1482m² - 624m²
= 858m².
The compact parking spaces that will fit in the lot will be:
N × 12.5 = 858
N = 858/12.5
N = 68
The non compact parking spaces that will fit in the lot will be:
N × 16.5 = 858
N = 858/16.5
N = 52
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Answer:
.99815
which is about
99.815%
Step-by-step explanation:
we are looking for 35<x<77
We need to find (what I think is called) the z score which is acheieved through what I'm pretty sure is called standardizing
What we do is subtract the mean and then divide by the standard deviation
so for 35 we have
(35-56)/7= -3.29
due to the fact that the normal distribution is symmetric this is equal to 1-p(3.29)
to find p(3.29) grab a ztable and get p(3.29)= .9995
1-.9995= .0005
For 77 we have
(77-56)/7=3
grab a ztable and find the 3= .99865
Finally subtract these two to get the final answer
.99865-.0005= .99815
Answer:
B. 0
Step-by-step explanation:
Given
g(t) = t² - t
f(x) = 1 + x
Required
Find g(f(3) - 2f(1))
First, we'll solve for f(3)
Given that f(x) = 1 + x
f(3) = 1 + 3
f(3) = 4
Then, we'll solve for 2f(1)
2f(1) = 2 * f(1)
2f(1) = 2 * (1 + 1)
2f(1) = 2 * 2
2f(1) = 4
Substitute the values of f(3) and 2f(1) in g(f(3) - 2f(1))
g(f(3) - 2f(1)) = g(4 - 4)
g(f(3) - 2f(1)) = g(0)
Now, we'll solve for g(0)
Given that g(t) = t² - t
g(0) = 0² - 0
g(0) = 0 - 0
g(0) = 0
Hence, g(f(3) - 2f(1)) = 0
From the list of given options, the correct answer is B. 0
Answer:
and Liz can ship maximum 19.6 pounds.
Step-by-step explanation:
Let the possible weight of the medium flat-rate box = w pounds.
It is given that there is a box weighing 6 ounces i.e. 0.375 pounds.
Plus, the maximum weight of the package is 20 pounds.
So, we get,
The inequality representing the situation is,
Weight of medium box + 0.375 pounds ≤ Maximum weight of the package
i.e.
i.e. 
i.e. 
Thus, Liz can ship maximum 19.6 pounds.
