HELP WITH CALCULUS!

Mathematics

1 answer:

padilas [110]3 years ago

3 0

Answer:yo bro i know the answer im spaming u lol and im scaming yo

Step-by-step explanation:

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Solve X showing every step

LenKa [72]

Answer:

no solution

Step-by-step explanation:

2x-5=8x+7-6x

2x-5=2x+7

-5=7

Not true so no solution

3 0

3 years ago

Find 2 consecutive positive even integers such that the product of the 1st and 2nd is 2 less than 5 times the 3rd. Use an algebr

Aloiza [94]

Assume the smaller one is x, then the other ones will be x+2 and x+4

x(x+2) + 2 = 5(x+4)

x^2 + 2x - 5x - 18 = 0

-> x^2 - 3x - 18 = 0

-> (x-6)(x+3) = 0

-> x = 6 or -3, since x must be positive, then x = 6

So the numbers are: 6, 8, 10

6 0

3 years ago

Jarvis left out a statement from the proof shown.which statement is best explained by the corresponding angles postulate

Salsk061 [2.6K]

The postulate of the corresponding angles establishes that when a transversal line cuts two parallel lines, the corresponding angles are congruent. These angles are on the same side of the parallel lines and on the same side of the transversal line.

Then, if we based on this definition and analize the figure attached, we can notice that the angles ∠1 and ∠3 are corresponding angles, so they are congruent. In this case the angle ∠1 is internal and the angle ∠3 is external.

The answer is: ∠1 and ∠3 are congruent (See the image attached).

7 0

3 years ago

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Which strategy best explains how to solve this problem?

Rufina [12.5K]

This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number

In this case we have r=2 and a=1 so

a(n)=2^(n-1) so on the sixth week he will run:

a(6)=2^5=32

He will run 32 blocks by the end of the sixth week.

Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:

s(n)=a(1-r^n)/(1-r) where the variables have the same values so

s(n)=(1-2^n)/(1-2)

s(n)=2^n-1 so

s(6)=2^6-1

s(6)=64-1

s(6)=63 blocks

So he would run a total of 63 blocks in the six weeks.

4 0

3 years ago

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Graph f(x)=sin (3.14/4)x

crimeas [40]

Answer:

Step-by-step explanation:

6 0

3 years ago