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3 years ago

The square root of 801025

Mathematics

2 answers:

snow_lady [41]3 years ago

8 0

Answer:

895

Step-by-step explanation: "hope this helps" :3

Ket [755]3 years ago

6 0

answer:

895

Step-by-step explanation:

You might be interested in

ms. guerra picked 32 students to help her decorate her door. she picked 8 more girls than boys. what is the experimental probabi

katrin2010 [14]

Answer:

5/8

Step-by-step explanation:

First we need to figure out how many girls and boys there are.

g = girls

b = boys

g = b+8 ( eight more girls than boys)

b = g-8

There are 32 students)

g+b =32

Substitute b = g-8 into the equation

g + (g-8) = 32

Combine like terms.

2g-8 = 32

Add 8 to each side.

2g -8+8 = 32+ 8

2g = 40

Divide by 2

g = 20

There are 20 girls

The experimental probability of picking a girl is

girls/ total

20/32 = 5/8

4 0

3 years ago

Suppose μ1 and μ2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of bra

Stella [2.4K]

Answer:

The 95% confidence interval would be given by $-23.44 \leq \mu_1 -\mu_2 \leq -8.16$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =114.1$ represent the sample mean 1

$\bar X_2 =129.9$ represent the sample mean 2

n1=5 represent the sample 1 size

n2=2 represent the sample 2 size

$s_1 =5.08$ sample standard deviation for sample 1

$s_2 =5.37$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

Confidence interval

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =114.1-129.9=-15.8$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_1 +n_2 -1=5+5-2=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=\pm 2.31$