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Murljashka [212]

2 years ago

15

Which expression models this phrase? 27 decreased by the difference of a number and 3 A. (n – 3) – 27 B. 27 – n + 3 C. 27 – (n –

3) D. 27 – n – 3

2 answers:

inysia [295]2 years ago

7 0

The answer is c because you have to say 27 minus the number minus 3

Shtirlitz [24]2 years ago

7 0

The answer is six becuase well its simple

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Find the 14th term of the geometric sequence 10,40,160

Galina-37 [17]

Answer:

671,088,640.

Step-by-step explanation:

To determine the 14th term of the geometric sequence that begins with 10, 40 and 160, knowing that each number is multiplied by 4, the following calculation must be performed, taking into account that the initial number (10) is multiplied by 4, and that said number must be potentiated 13 times to obtain the 14th term:

10 x (4 ^ 13) = X

10 x 67,108,864 = X

671,088,640 = X

Therefore, the 14th term of the geometric sequence will be 671,088,640.

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What is 4×3^2-3+5×2=

stepladder [879]

86 opposite of it so it would be87

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2 years ago

How does adding the log together automatically mean that it is a factorial?

andreyandreev [35.5K]

Answer: The answer is given below.

Step-by-step explanation: We are given an equality involving logarithm and we are to show the implication of L.H.S. to R.H.S.

We will be using the following two properties of logarithm:

$(i)~\log_ba=\dfrac{1}{\log_ab},\\\\\\(ii)~log_ab+\log_ac=\log_a(bc).$

The proof is as follows:

$L.H.S.\\\\\\=\dfrac{1}{\log_2N}+\dfrac{1}{\log_3N}+\dfrac{1}{\log_4N}+\cdots+\dfrac{1}{\log_{100}N}\\\\\\=\log_N2+\logN3+\log_N4+\cdots+\log_N100\\\\=\log_N\{2.3.4...100\}\\\\=\log_N\{1.2.3.4...100\}\\\\=\log_N{100!}\\\\=\dfrac{1}{\log_{100!}N}\\\\=R.H.S.$

Hence proved.

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2 years ago