Answer:
593775ways
Step-by-step explanation:
Combination has to do with selection of r objects from a total number of n objects and this can be done in nCr ways. Generally,
nCr = n!/(n-r)!r!
Since the math teacher has to select 6 students from a class of 30, this can be done in 30C6 number of ways to have;
30C6 = 30!/(30-6)!6!
30C6 = 30!/24!6!
30C6 = 30×29×28×27×26×25×24!/24!×6×5×4×3×2
30C6 = 30×29×28×27×26×25/6×5×4×3×2
30C6 = 427,518,000/720
30C6 = 593775ways
This means, the selection can be made in 593775ways
The answer is - 2c/3
I think it may be H. but let me know if i am wrong. if i am right plz mark brainliest
27 divided by 3 is 9, 27/3=9 because 27/3 is the same exact thing as 27 divided by 3. So the answer has to be 9