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zmey [24]
2 years ago
7

Simplify (-8)(-2) + 11​

Mathematics
1 answer:
Zina [86]2 years ago
5 0

9 is the answer good luck

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Write a function using function notation to describe each situation. Find a reasonable domain and range for each function.
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F(t)= 7.00 x t + 55 A reasonable domain is (0,1,2,3). The range is ($55,$62,$69,$76)
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Identify the common external tangent.<br><br> line r<br> line s<br> segment AB
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The external tangent is line s
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Please help with the following problem asap!!
umka21 [38]

Answer:

8^7

Step-by-step explanation:

\dfrac{8^{15}}{8^7 \cdot 8} =

Remember that 8 = 8^1.

= \dfrac{8^{15}}{8^7 \cdot 8^1}

When you multiply powers with the same base, add the exponents. Do this in the denominator.

= \dfrac{8^{15}}{8^{7+1}}

= \dfrac{8^{15}}{8^{8}}

When  you divide powers with the same base, subtract the exponents.

= 8^{15-8}

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4 0
3 years ago
So in numeric form what is 700,000+40,000+9000+200 and +50
WARRIOR [948]

Answer: 749,250

Step-by-step explanation:

700,000 + 40,000= 740,000.

9,000+200+50= 9,250.

740,000 + 9,250 = 740,250.

4 0
3 years ago
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If 2^n + 1 is an odd prime for some integer n, prove that n is a power of 2. (H
vovikov84 [41]

Step-by-step explanation:

We will prove by contradiction. Assume that 2^n + 1 is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that p\mid n. Then, for some integer k\geq 1,

n=p\times k.

Therefore

  1. 2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p.

Here we will use the formula for the sum of odd powers, which states that, for a,b\in \mathbb{R} and an odd positive number n,

a^n+b^n=(a+b)(a^{n-1}-a^{n-2}b+a^{n-3}b^2-...+b^{n-1})

Applying this formula in 1) we obtain that

2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p=(2^k+1)(2^{k(p-1)}-2^{k(p-2)}+...-2^{k}+1).

Then, as 2^k+1>1 we have that 2^n+1 is not a prime number, which is a contradiction.

In conclusion, if 2^n+1 is an odd prime, then n must be a power of 2.

4 0
3 years ago
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