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77julia77 [94]
3 years ago
8

Tanya bought two adult tickets and one children's ticket to a movie for $15.90. Li bought four adult tickets and four children's

tickets for $38.40. Find the cost of one adult ticket and the cost of one children's ticket.

Mathematics
1 answer:
Fiesta28 [93]3 years ago
6 0
The answer, hopefully you will understand

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RoseWind [281]

Answer:c

Step-by-step explanation:

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50 POINTS!!!!!!!!!!<br><br><br> Solve for EG.<br> A) 12 <br> B) 15 <br> C) 21 <br> D) 30
Sergio039 [100]
The answer is C) 21, because 6/14 is simplified to 3/7. assuming it’s a pattern 3/7, 6/14, 12/21.
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3 years ago
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Nemo rents 5 movies per month when the price is $3.00 per rental and 7 movies per month when the price is $2.50 per rental. nemo
yuradex [85]
The law of supply<span> states that the quantity of a good </span>supplied<span> (i.e., the amount owners or producers offer for sale) rises as the market price rises, and falls as the price falls. Conversely, the </span>law<span> of </span>demand<span> (see </span>demand<span>) says that the quantity of a good demanded falls as the price rises, and vice versa.</span>
6 0
3 years ago
A soccer ball is kicked from 3 feet above the ground. the height,h, in feet of the ball after t seconds is given by the function
dexar [7]
Here's our equation.

h=-16t+64t+3

We want to find out when it returns to ground level (h = 0)

To find this out, we can plug in 0 and solve for t.

0 = -16t+64t+3 \\ 16t-64t-3=0 \\ use\ the\ quadratic\ formula\ \frac{-b\±\sqrt{b^2-4ac}}{2a}  \\ \frac{-(-64)\±\sqrt{(-64)^2-4(16)(-3)}}{2*16}  = \frac{64\±\sqrt{4096+192}}{32}

= \frac{64\±\sqrt{4288}}{32} = \frac{64\±8\sqrt{67}}{32} = \frac{8\±\sqrt{67}}{4} = \boxed{\frac{8+\sqrt{67}}{4}\ or\ 2-\frac{\sqrt{67}}{4}}

So the ball will return to the ground at the positive value of \boxed{\frac{8+\sqrt{67}}{4}} seconds.

What about the vertex? Simple! Since all parabolas are symmetrical, we can just take the average between our two answers from above to find t at the vertex and then plug it in to find h!

\frac{1}2(\frac{8+\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(2+\frac{\sqrt{67}}{4}+2-\frac{\sqrt{67}}{4}) = \frac{1}2(4) = 2

h=-16t^2+64t+3 \\ h=-16(2)^2+64(2)+3 \\ \boxed{h=67}


8 0
3 years ago
1 point<br> Captionless Image
algol [13]

Answer:

uhhh ok

Step-by-step explanation:

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