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3 years ago

Which of the following formulas could be used to find the perimeter, P, of a regular hexagon? brainleist

Mathematics

1 answer:

uysha [10]3 years ago

5 0

Answer:

P = 6s

Step-by-step explanation:

Hexagon is a closed figure that have 6 sides. Perimeter of a figure is equal to the sum of all sides.

Let s is the sides of all hexagon such that the perimeter of a regular hexagon becomes :

Perimeter = s+s+s+s+s+s

P = 6s

Perimeter of a regular hexagon is equal to 6 times of its sides. Hence, the correct option is (c).

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Help please! 10 points!

IgorC [24]

Answer:

21.6 or 22

Step-by-step explanation:

Triangles have same angles. This means that they are proportion.

50/27 = 40/x

when you cross multiply to solve x, 50x = 1080

so x = 21.6

If you have to nearest whole number, it will be 22

7 0

3 years ago

Question:

-Dominant- [34]

C I took the tests on eg today

6 0

3 years ago

Solve pls brainliest

Drupady [299]

91/25, 3.92, 3.928, 2 13/20

im pretty sure this is correct AND IM RLY SRY IF IT ISN’T

7 0

2 years ago

Last year, 800 students attended the career fair at west high school. this year,the number of students who attended the career f

Delvig [45]

Answer:

840

Step-by-step explanation:

Last year, 800 students attended the career fair at West High School.

And, this year the number of students who attended the career fair increased by 5%.

We are asked how many students attended the career fair at West High School this year.

Therefore, the number of students attended the career fair at West High School will be $800[1+\frac{5}{100} ] =800 \times 1.05 = 840$ . (Answer)

3 0

3 years ago

Determine if the following system of equations has no solutions 4x+3y= -8 -8x-6y= 16

cupoosta [38]

$\begin{cases} 4x+3y=-8\\\\ -8x-6y=16 \end{cases}~\hspace{10em} \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$4x+3y=-8\implies 3y=-4x-8\implies y=\cfrac{-4x-8}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}} x-\cfrac{8}{3} \\\\[-0.35em] ~\dotfill\\\\ -8x-6y=16\implies -6y=8x+16\implies y=\cfrac{8x+16}{-6} \\\\\\ y=\cfrac{8}{-6}x+\cfrac{16}{-6}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}} x-\cfrac{8}{3}$

one simple way to tell if both equations do ever meet or have a solution is by checking their slope, notice in this case the slopes are the same for both, meaning the lines are parallel lines, however, notice both equations are really the same, namely the 2nd equation is really the 1st one in disguise.

since both equations are equal, their graph will be of one line pancaked on top of the other, and the solutions is where they meet, hell, they meet everywhere since one is on top of the other, so infinitely many solutions.

3 0

2 years ago