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SVETLANKA909090 [29]
3 years ago
7

Write a quadratic function that only has one root

Mathematics
1 answer:
AlekseyPX3 years ago
3 0

Answer:

y= x squared.

Step-by-step explanation:

When graphed, the parabola only has an x-intercept at (0,0). Since a root is another word for an x-intercept, it only has one root.

I hope this helps, and I hope you have a good day.

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Spencer wants to burn 450 calories while biking. Biking burns about 10 calories per minute. When Spencer goes biking, he usually
kupik [55]

Answer:

The equation  to find the total number of minutes (including rest) that Spencer should plan to be out biking is 10(m-15)=450.

Spencer should plan for 60 minutes  to be out biking.

Step-by-step explanation:

Given:

Total calories need to burn = 450 calories

Calories burn per minute = 10

number of minutes he rest = 15

We need to find the total number of minutes (including rest) that Spencer should plan to be out biking.

Solution:

Let Total minutes of biking be 'm'.

So we can say that.

Calories burn per minute multiplied by the difference of total minutes and number of minutes he rest is equal to Total calories need to burn.

framing in equation form we get;

10(m-15)=450

Hence the equation  to find the total number of minutes (including rest) that Spencer should plan to be out biking is 10(m-15)=450.

On Solving the above equation we get;

First we will divide both side by 10 we get;

\frac{10(m-15)}{10}=\frac{450}{10}\\\\m-15=45

Now adding both side by 15 we get;

m-15+15=45+15\\\\m=60\ minutes

Hence Spencer should plan for 60 minutes  to be out biking.

4 0
3 years ago
Differentiate<br> y=(6x)/(1-cot(x))
My name is Ann [436]
\bf y=\cfrac{6x}{1-cot(x)}\implies \cfrac{dy}{dx}=\stackrel{quot ient~ru le}{\cfrac{6[1-cot(x)]~-~6x[-csc^2(x)]}{[1-cot(x)]^2}}&#10;\\\\\\&#10;\cfrac{dy}{dx}=\cfrac{6-6cot(x)~+~6xcsc^2(x)}{[1-cot(x)]^2}
8 0
3 years ago
What are the roots of the polynomial equation? (picture below)
Marat540 [252]

Answer:

x = - 9, x = 0, x = 7

Step-by-step explanation:

Given

\frac{1}{2} x(x - 7)(x + 9) = 0 ← in standard form

Equate each factor to zero and solve for x

\frac{1}{2} x = 0 ⇒ x = 0

x - 7 = 0 ⇒ x = 7

x + 9 = 0 ⇒ x = - 9

3 0
2 years ago
Read 2 more answers
Complete the table of values for y =6-2x
sertanlavr [38]

Answer:

k

Step-by-step explanation:

x=0 y=6

x=1 y=4

x=2 y=2

x=3 y=0

x=4 y=-2

x=5 y=-4

u basically get the pattern

5 0
3 years ago
Is the gcf of a pair of numbers ever equal to one of the numbers
Marianna [84]
No it's a number that can be found in both of the factor lists.
3 0
3 years ago
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