Answer:
The assumption of homoscedasticity is that "<u>the variability of Y doesn't change over the X scores</u>."
Step-by-step explanation:
The assumptions of linear regression are:
- Linear relationship
- Multivariate normality
- Almost 0 mulitcollinearity
- 0 Autocorrelation
- Homoscedasticity
The assumption of homoscedasticity implies that the variance of the dependent variable <em>Y</em>, across the regression line does not changes for all values of the predictor variable <em>X</em>.
Thus, the complete statement is:
The assumption of homoscedasticity is that "<u>the variability of Y doesn't change over the X scores</u>."
Answer:
From this info and using the empirical rule we know that we will have about 68% of the scores between:
95 % of the scores between:
And 99.7% of the values between
Step-by-step explanation:
For this problem we can define the random variable of interest as "the student grades" and we know that the distribution for X is given by:
From this info and using the empirical rule we know that we will have about 68% of the scores between:
95 % of the scores between:
And 99.7% of the values between
So
bowl is a half sphere
cylinder is a cylninder
cone is cone
bowl:
area of circle=4/3 pi times r^3
half bowl=4/3 times 1/2 times pi times r^3=2/3pi r^3
cylinder=height times pi times radius^2
this cylinder=r times pi times r^2=pi times r^3
cone=1/3 times height times pi times radius^2
thgis cone=1/3 times r tiimes pi times r^2=1/3 times pi times r^3
compare
bowl=2/3 pi r^3
cylinder=pi r^3
cone=1/3 pi r^3
the cylinder is biggest
CYLINDER IS THE ANSWER
2.
sphwere=4/3 times radius^3 times pi
this sphere=4/3 times pi times r^3
cylinder=height times radius^2 time pi
this cylinder=2r times r^2 times pi=2r^3 times pi
cone=1/3 times height time r^2 times pi
this cone=1/3 times 2r times r^2 times pi=1/3 times 2r^3 times pi=2/3 times r^3 times pi
sphere:4/3 pi r^3
cylinder: 2 pi r^3
cone: 2/3 pi r^3
Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).