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Allisa [31]
3 years ago
9

Which of the two solids below are similar ?

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0

Answer:  I and II.

Step-by-step explanation:

By definition, two solids are similar if their corresponding sides are in the same ratio.

Knowing this, let's find which solids are similar:

Corresponding sides ratio of solids I and II:

\frac{3}{2}=\frac{2}{\frac{4}{3}}=\frac{5}{\frac{10}{3}}

\frac{3}{2}=\frac{3}{2}=\frac{3}{2}

Corresponding sides ratio of solids I and III:

\frac{3}{\frac{9}{2}}=\frac{2}{3}=\frac{5}{8}

\frac{2}{3}=\frac{2}{3}=\frac{5}{8}

Corresponding sides ratio of solids II and III:

\frac{2}{\frac{9}{2}}=\frac{\frac{4}{3}}{3}}=\frac{\frac{10}{3}}{8}}

\frac{4}{9}=\frac{4}{9}=\frac{5}{12}

 You can observe that the solids  I and II are similar.

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b = 9 {n}^{2}  + 7

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{a}^{2}  = ( {3n + 4})^{2}

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b = 9 {n}^{2}  + 7

b = 9 {n}^{2}  + 24n - 24n + 7 + 9 - 9 \\

b = (9 {n}^{2}  + 24n + 16)  - 24n - 9 - 23 + 23 \\

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