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3 years ago

6

T is the midpoint of SU. Find ST, TU and SU. 10x-14 5x+16S———T———U

1 answer:

jeka943 years ago

6 0

since T is the midpoint of SU, then ST = TU.

$\bf \stackrel{10x-14}{\boxed{S}\rule[0.35em]{10em}{0.25pt}} T\stackrel{5x+16}{\rule[0.35em]{10em}{0.25pt}\boxed{U}} \\\\\\ \stackrel{ST}{10x-14}=\stackrel{TU}{5x+16}\implies 5x-14=16\implies 5x=30\implies x=\cfrac{30}{5}\implies x=6 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ST}{10(6)-14\implies 46}~\hfill \stackrel{TU}{TU=ST=46}~\hfill \stackrel{SU}{ST+TU=92}$

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a.) 0.5

b.) 0.66

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Step-by-step explanation:

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Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

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Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

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= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

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= 1× $\frac{6.5.4}{3.2.1! }$

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c.)

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