Please elaborate on your question so I can help you..
Answer:
First five terms are:
4300, 4240, 4180, 4120, 4060
Step-by-step explanation:
Minus 60 from the predicted number of cars in the first month to get the second month, then do the same for the predicted number of cars in the second month to get the third month and so on.
The expression for the nth term would be = 4300 - (n-1)(60)
= 4360 - 60n
Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
Answer:
The answer to your question is: g(3) = 34
Step-by-step explanation:
Function g(x) = 4(x)² - 3(x) + 7
g(3) = 4(3)² - 3(3) + 7 substitution
g(3) = 4(9) - 3(3) + 7 simplify
g(3) = 36 - 9 + 7
g(3) = 36 - 2
g(3) = 34
