Given
A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.
To find:
The area of the park excluding the court at the rate of Rs 110 per square meter.
Solution:
Area of a rectangle is:
Area of whole park is:
Area of volleyball court is:
Now, the area of the park excluding the court is:
Therefore, the area of the park excluding the court is 2820 square meter.
To solve the equation using complete square method we proceed:
z^2-19z=66
but
c=(-b/2a)^2
c=(-19/2)^2
c=361/4
thus:
z^2-19z+361/4=66+361/4
factoring the LHS we get:
1/4(2z-19)^2=625/4
(2z-19)^2=625
getting the square root of both sides we get:
2z-19=+/-25
2z=+/-25+19
2z=44 or -6
z=22 or -3
Answer: z=22 or z=-3
Add the three angles and set them to 180
4x-13+15+x+18=180
5x+20=180
5x=160
x=32
Then plug in to get A and C
A=4*32-13
A=115
C=32+18
C=50
Answer:
100 km squared
Step-by-step explanation:
Front : 14
Back : 14
Top : 28
Bottom : 28
Side : 8
Side : 8
Surface area : 100 km squared
Hope this helps!
Answer:
203
Step-by-step explanation:
14×14.50=203 I calculated it
